TypeError: only length-1 arrays can be converted to Python scalars while plot showing

Question

I have such Python code:

import numpy as np
import matplotlib.pyplot as plt

def f(x):
    return np.int(x)

x = np.arange(1, 15.1, 0.1)
plt.plot(x, f(x))
plt.show()

And such error:

TypeError: only length-1 arrays can be converted to Python scalars

How can I fix it?

Asked By: K. Kovalev

||

Source

Answer 1

Take note of what is printed for x. You are trying to convert an array (basically just a list) into an int. length-1 would be an array of a single number, which I assume numpy just treats as a float. You could do this, but it’s not a purely-numpy solution.

EDIT: I was involved in a post a couple of weeks back where numpy was slower an operation than I had expected and I realised I had fallen into a default mindset that numpy was always the way to go for speed. Since my answer was not as clean as ayhan’s, I thought I’d use this space to show that this is another such instance to illustrate that vectorize is around 10% slower than building a list in Python. I don’t know enough about numpy to explain why this is the case but perhaps someone else does?

import numpy as np
import matplotlib.pyplot as plt
import datetime

time_start = datetime.datetime.now()

# My original answer
def f(x):
    rebuilt_to_plot = []
    for num in x:
        rebuilt_to_plot.append(np.int(num))
    return rebuilt_to_plot

for t in range(10000):
    x = np.arange(1, 15.1, 0.1)
    plt.plot(x, f(x))

time_end = datetime.datetime.now()

# Answer by ayhan
def f_1(x):
    return np.int(x)

for t in range(10000):
    f2 = np.vectorize(f_1)
    x = np.arange(1, 15.1, 0.1)
    plt.plot(x, f2(x))

time_end_2 = datetime.datetime.now()

print time_end - time_start
print time_end_2 - time_end

Answered By: roganjosh

Answer 2

The error "only length-1 arrays can be converted to Python scalars" is raised when the function expects a single value but you pass an array instead.

np.int was an alias for the built-in int, which is deprecated in numpy v1.20. The argument for int should be a scalar and it does not accept array-like objects. In general, if you want to apply a function to each element of the array, you can use np.vectorize:

import numpy as np
import matplotlib.pyplot as plt

def f(x):
    return int(x)
f2 = np.vectorize(f)
x = np.arange(1, 15.1, 0.1)
plt.plot(x, f2(x))
plt.show()

You can skip the definition of f(x) and just pass the function int to the vectorize function: f2 = np.vectorize(int).

Note that np.vectorize is just a convenience function and basically a for loop. That will be inefficient over large arrays. Whenever you have the possibility, use truly vectorized functions or methods (like astype(int) as @FFT suggests).

Answered By: ayhan

Answer 3

Use:

x.astype(int)

Here is the reference.

Answered By: FFT

Answer 4

dataframe['column'].squeeze() should solve this. It basically changes the dataframe column to a list.

Answered By: Nkem Omede

Answer 5

In this case the output has to be a rounded int values.

import numpy as np

arr = np.array([2.34, 2.56, 3.12])
output = np.round(arr).astype(int)

print(output)
# array([2, 3, 3])

Answered By: niek tuytel

Answer 6

import numpy as np
import matplotlib.pyplot as plt

def f(x):
    return np.array(list(map(np.int, x)))

x = np.arange(1, 15.1, 0.1)
plt.plot(x, f(x))
plt.show()

using np.array(list(map(np.int, x))) will converge numpy array to scaler value and fix the issue for more detail visit this detailed article.

Answered By: Abhishek Trivedi

TypeError: only length-1 arrays can be converted to Python scalars while plot showing

Question:

Answers: