"TypeError: object of type 'Response' has no len()"

Question:

When I try to execute the code

BeautifulSoup(html, ...)

it gives the error message

TypeError: object of type ‘Response’ has no len()

I tried passing the actual HTML as a parameter, but it still doesn’t work.

import requests

url = 'http://vineoftheday.com/?order_by=rating'
response = requests.get(url)
html = response.content

soup = BeautifulSoup(html, "html.parser")
Asked By: Bryan

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Source

Answers:

Try to pass the HTML text directly

soup = BeautifulSoup(html.text)
Answered By: Jorge

You are getting response.content. But it return response body as bytes (docs). But you should pass str to BeautifulSoup constructor (docs). So you need to use the response.text instead of getting content.

Answered By: Matvei Nazaruk

If you’re using requests.get('https://example.com') to get the HTML, you should use requests.get('https://example.com').text.

Answered By: Moshe G

you are getting only response code in ‘response’
and always use browser header for security otherwise
you will face many issues

Find header in debugger console network section ‘header’ UserAgent

Try

import requests
from bs4 import BeautifulSoup

from fake_useragent import UserAgent

url = 'http://www.google.com'
headers = {'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_13_6) 
AppleWebKit/537.36 (KHTML, like Gecko) Chrome/71.0.3578.98 Safari/537.36'}

response = requests.get(quote_page, headers=headers).text

soup = BeautifulSoup(response, 'html.parser')
print(soup.prettify())
Answered By: Atul

It worked for me:

soup = BeautifulSoup(requests.get("your_url").text)

Now, this code below is better (with lxml parser):

import requests
from bs4 import BeautifulSoup

soup = BeautifulSoup(requests.get("your_url").text, 'lxml')
Answered By: Ozcar Nguyen

you should use .text to get content of response

import  requests
url = 'http://www ... '
response = requests.get(url)
print(response.text)

or use with soap

import  requests
from bs4 import BeautifulSoup

url = 'http://www ... '
response = requests.get(url)
msg = response.text
print(BeautifulSoup(msg,'html.parser'))
Answered By: mamal
import requests
from urllib.request import urlopen
from bs4 import BeautifulSoup
import re

url = "https://fortnitetracker.com/profile/all/DakshRungta123"
html = requests.get(url)

soup = BeautifulSoup(html)


title = soup.text
print(title.text)
Answered By: ddddd

html.parser is used to ignore the warnings in the page:

soup = BeautifulSoup(html.text, "html.parser")
Answered By: Heba Allah. Hashim
import requests

url = 'http://vineoftheday.com/?order_by=rating'
response = requests.get(url)
html = response.content

soup = BeautifulSoup(html.text, "html.parser")
Answered By: BiswajitPaloi