TypeError: list indices must be integers or slices, not list

Question

array = some kind of list with 3 columns and unlimited amount of rows with data inside of it.

Volume = array[0][2] 
counter = 0
for i in array: 
    if Volume == array[i][2]: #<------ why is this line a problem? 
        counter += 1

Asked By: Michael

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Source

Answer 1

This is a classic mistake. i in your case is already an element from array (i.e. another list), not an index of array (not an int), so

if Volume == i[2]:
    counter += 1

You can check the Python tutorial. Also, try doing this:

for i in array:
    print (i)

And see what you get!

Also I would advise to stick to naming conventions: variables are normally lower-case (volume, not Volume). In this case i is misleading. row or elem would be much more suitable.

Answered By: Piotr Ćwiek

Answer 2

Also, as this may happen frequently, note that you cannot access slices of lists (but you can for an array):

import numpy as np
integerarray = np.array([33,11,22], dtype=int)
integerlist = [33,11,22]
indexArray = [1,2,0]  # or equivalently, an array, e.g. np.argsort(integerlist)
print(integerarray[indexArray]) ## works fine
print(integerlist[indexArray])  ## triggers: TypeError: list indices must be integers or slices, not list

I hope this helps.
It even happened to me that I had to convert to a float array, otherwise the object would remain of the wrong type.

Answered By: François Landes

TypeError: list indices must be integers or slices, not list

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