Selenium-Debugging: Element is not clickable at point (X,Y)

Question:

I try to scrape this site by Selenium.

I want to click in "Next Page" buttom, for this I do:

driver.find_element_by_class_name('pagination-r').click()

it works for many pages but not for all, I got this error

WebDriverException: Message: Element is not clickable at point (918, 13). Other element would receive the click: <div class="linkAuchan"></div>

always for this page

I read this question

and I tried this

driver.implicitly_wait(10)
el = driver.find_element_by_class_name('pagination-r')
action = webdriver.common.action_chains.ActionChains(driver)
action.move_to_element_with_offset(el, 918, 13)
action.click()
action.perform()

but I got the same error

Asked By: parik

||

Answers:

Another element is covering the element you are trying to click. You could use execute_script() to click on this.

element = driver.find_element_by_class_name('pagination-r')
driver.execute_script("arguments[0].click();", element)
Answered By: RemcoW

Use explicit wait instead of implicit.

new WebDriverWait(TestingSession.Browser.WebDriver, TimeSpan.FromSeconds(10)).Until(ExpectedConditions.ElementExists((By.ClassName("pagination-r'")))); 
Answered By: Rakesh Raut

I had a similar issue where using ActionChains was not solving my error:
WebDriverException: Message: unknown error: Element is not clickable at point (5
74, 892)

I found a nice solution if you dont want to use execute_script:

from selenium.webdriver.common.keys import Keys #need to send keystrokes

inputElement = self.driver.find_element_by_name('checkout')

inputElement.send_keys("n") #send enter for links, buttons

or

inputElement.send_keys(Keys.SPACE) #for checkbox etc
Answered By: Deepak Garud

If you are receiving an element not clickable error, even after using wait on the element, try one of these workarounds:

  • Use Action to move to the location of element and then run perform on action
WebElement element = driver.findElement(By("element_path"));
Actions actions = new Actions(driver);
actions.moveToElement(element).click().perform();`
  • Check for an overlay or spinner on the element and wait for its invisibility
By spinnerimg = By.id("spinner ID");
WebDriverWait wait = new WebDriverWait(driver, timeOutInSeconds);
wait.until(ExpectedConditions.invisibilityOfElementLocated(spinnerimg ));

Hope this helps

Answered By: quickauto

I have written logic to handle these type of exception .

   def find_element_click(self, by, expression, search_window=None, timeout=32, ignore_exception=None,
                       poll_frequency=4):
    """It find the element and click then  handle all type of exception during click

    :param poll_frequency:
    :param by:
    :param expression:
    :param timeout:
    :param ignore_exception:list It is a list of exception which is need to ignore.
    :return:
    """
    if ignore_exception is None:
        ignore_exception = []

    ignore_exception.append(NoSuchElementException)
    if search_window is None:
        search_window = self.driver

    end_time = time.time() + timeout
    while True:
        try:
            web_element = search_window.find_element(by=by, value=expression)
            web_element.click()
            return True
        except tuple(ignore_exception) as e:
            self.logger.debug(str(e))
            if time.time() > end_time:
                self.logger.exception(e)
                time.sleep(poll_frequency)
                break
        except Exception as e:
            raise
    return False
Answered By: Chetan Kolhe

Because element is not visible on the browser, first you need to scroll down to the element
this can be performed by executing javascript.

element = driver.find_element_by_class_name('pagination-r')
driver.execute_script("arguments[0].scrollIntoView();", element)
driver.execute_script("arguments[0].click();", element)
Answered By: Smart Dev

I had the similar issue with Chrome driver, changing the PageLoadStrategy of chromeOptions from ‘Eager’ to Normal fixed my problem.

chromeOptions.PageLoadStrategy = PageLoadStrategy.Normal;
Answered By: Rajat Maheshwari