public int[] range(int start, int length) {
    int[] range = new int[length - start + 1];
    for (int i = start; i <= length; i++) {
        range[i - start] = i;
    }
    return range;
}

(Long answer just to say “No”)

public int[] range(int start, int stop)
{
   int[] result = new int[stop-start];

   for(int i=0;i<stop-start;i++)
      result[i] = start+i;

   return result;
}

Forgive any syntax or style errors; I normally program in C#.

If you mean to use it like you would in a Python loop, Java loops nicely with the for statement, which renders this structure unnecessary for that purpose.

I’m working on a little Java utils library called Jools, and it contains a class Range which provides the functionality you need (there’s a downloadable JAR).
Constructors are either Range(int stop), Range(int start, int stop), or Range(int start, int stop, int step) (similiar to a for loop) and you can either iterate through it, which used lazy evaluation, or you can use its toList() method to explicitly get the range list.

for (int i : new Range(10)) {...} // i = 0,1,2,3,4,5,6,7,8,9

for (int i : new Range(4,10)) {...} // i = 4,5,6,7,8,9

for (int i : new Range(0,10,2)) {...} // i = 0,2,4,6,8

Range range = new Range(0,10,2);
range.toList(); // [0,2,4,6,8]

Groovy’s nifty Range class can be used from Java, though it’s certainly not as groovy.

Since Guava 15.0, Range.asSet() has been deprecated and is scheduled to be removed in version 16. Use the following instead:

ContiguousSet.create(Range.closed(1, 5), DiscreteDomain.integers());

The “Functional Java” library allows to program in such a way to a limited degree, it has a range() method creating an fj.data.Array instance.

See:

• http://functionaljava.googlecode.com/svn/artifacts/3.0/javadoc/fj/data/Array.html#range%28int,%20int%29

Similarly the “Totally Lazy” library offers a lazy range method:
http://code.google.com/p/totallylazy/

Old question, new answer (for Java 8)

IntStream.range(0, 10).forEach(n -> System.out.println(n));

or with method references:

IntStream.range(0, 10).forEach(System.out::println);

You can use the following code snippet in order to get a range set of integers:

    Set<Integer> iset = IntStream.rangeClosed(1, 5).boxed().collect
            (Collectors.toSet());

Java 9 – IntStream::iterate

Since Java 9 you can use IntStream::iterate and you can even customize the step. For example if you want int array :

public static int[] getInRange(final int min, final int max, final int step) {
    return IntStream.iterate(min, i -> i < max, i -> i + step)
            .toArray();
}

or List :

public static List<Integer> getInRange(final int min, final int max, final int step) {
    return IntStream.iterate(min, i -> i < max, i -> i + step)
            .boxed()
            .collect(Collectors.toList());
}

And then use it :

int[] range = getInRange(0, 10, 1);

IntStream.range(0, 10).boxed().collect(Collectors.toUnmodifiableList());

I know this is an old post but if you are looking for a solution that returns an object stream and don’t want to or can’t use any additional dependencies:

Stream.iterate(start, n -> n + 1).limit(stop);

start – inclusive
stop – exclusive

Java 8

private static int[] range(int start, int stop, int step) {
    int[] result = new int[(stop-start)%step == 0 ? (stop-start)/step : (stop-start)/step+1];
    int count = 0;
    Function<Integer, Boolean> condition = step > 0 ? (x) -> x < stop : (x) -> x > stop;
    for (int i = start; condition.apply(i); i += step) {
        result[count] = i;
        count++;
    }
    return result;
}