Set specific DNS server using dns.resolver (pythondns)

Question:

I am using dns.resolver from dnspython.

Is it possible to set the IP address of the server to use for queries ?

Asked By: Massimo

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Answers:

You don’t specify in your question, but assuming you’re using the resolver from dnspython.org, the documentation indicates you want to set the nameservers attribute on the Resolver object.

Though it may be easier to provide an /etc/resolv.conf-style file to pass to the constructor’s filename argument.

Answered By: bstpierre

Although this is somewhat of an old thread, I will jump in. I’ve bumped against the same challenge and I thought I would share the solution. So, basically the config file would populate the ‘nameservers’ instance variable of the dns.resolver.Resolver you are using. Hence, if you want to coerce your Resolver to use a particular nameserver, you can do it direcly like this:

import dns.resolver

my_resolver = dns.resolver.Resolver()

# 8.8.8.8 is Google's public DNS server
my_resolver.nameservers = ['8.8.8.8']

answer = my_resolver.query('google.com')

Hope someone finds it useful.

Answered By: Marcin Wyszynski

Yes, it is.

If you use the convenience function dns.resolver.query() like this

import dns.resolver
r = dns.resolver.query('example.org', 'a')

you can re-initialize the default resolver such such a specific nameserver (or a list) is used, e.g.:

import dns.resolver
dns.resolver.default_resolver = dns.resolver.Resolver(configure=False)
dns.resolver.default_resolver.nameservers = ['8.8.8.8', '2001:4860:4860::8888',
                                             '8.8.4.4', '2001:4860:4860::8844' ]
r = dns.resolver.query('example.org', 'a')

Or you can use a separate resolver object just for some queries:

import dns.resolver
res = dns.resolver.Resolver(configure=False)
res.nameservers = [ '8.8.8.8', '2001:4860:4860::8888',
                    '8.8.4.4', '2001:4860:4860::8844' ]
r = res.query('example.org', 'a')
Answered By: maxschlepzig

Since there’s no example of how to do this with dnspython in 2021, I thought I’d post one:

import dns.resolver

resolver = dns.resolver.Resolver()
resolver.nameservers = ['8.8.8.8'] # using google DNS
result = resolver.resolve('google.com', 'NS')
nameservers = [ns.to_text() for ns in result]

Output:

['ns1.google.com.', 'ns3.google.com.', 'ns2.google.com.', 'ns4.google.com.']
Answered By: Amal Murali
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