print python stack trace without exception being raised

Question

Something is happening with one of my class’s instance variables. I want to make the variable a property, and whenever it is accessed I want to print out the stack trace of all the code leading up to that point, so I can see where it’s being messed with. How do I print out the stack trace when no exception has been raised? I know if there is an exception I can do something like traceback.format_tb(sys.exc_info()[2]).

Also what might be useful is to print only the last 3-4 levels, since the first few are probably not going to be that interesting.

Asked By: Claudiu

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Source

Answer 1

traceback.print_stack():

>>> def f():
...   def g():
...     traceback.print_stack()
...   g()
...
>>> f()
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 4, in f
  File "<stdin>", line 3, in g

Edit: You can also use extract_stack, take a slice (e.g. stack[5:] for exclude the first 5 levels) and use format_list to get a print-ready stacktrace ('n'.join(traceback.format_list(...)))

Answered By: user395760

Answer 2

Instead of printing to stdout, if you need a string to pass to a logger you can use:

''.join(traceback.format_stack())

Note, that traceback.format_stack() returns the stacktrace as a formatted list of strings, so you can slice it anyway you want. To get the last few elements of the stacktrace you could do:

''.join(traceback.format_stack()[-N:])

Where N is the number of levels you are interested in.

Answered By: rouble

Answer 3

traceprint will show you the stack calls that led to a print statement:

import traceprint

def func():
    print(f'Hello from func')

func()

#   File "/traceprint/examples/example.py", line 6, in <module>
#   File "/traceprint/examples/example.py", line 4, in func
# Hello from func

Answered By: 101

print python stack trace without exception being raised

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