How to convert Nonetype to int or string?

That TypeError only appears when you try to pass int() None (which is the only NoneType value, as far as I know). I would say that your real goal should not be to convert NoneType to int or str, but to figure out where/why you’re getting None instead of a number as expected, and either fix it or handle the None properly.

You should check to make sure the value is not None before trying to perform any calculations on it:

my_value = None
if my_value is not None:
    print int(my_value) / 2

Note: my_value was intentionally set to None to prove the code works and that the check is being performed.

int(value or 0)

This will use 0 in the case when you provide any value that Python considers False, such as None, 0, [], “”, etc. Since 0 is False, you should only use 0 as the alternative value (otherwise you will find your 0s turning into that value).

int(0 if value is None else value)

This replaces only None with 0. Since we are testing for None specifically, you can use some other value as the replacement.

This can happen if you forget to return a value from a function: it then returns None. Look at all places where you are assigning to that variable, and see if one of them is a function call where the function lacks a return statement.

A common "Pythonic" way to handle this kind of situation is known as EAFP for "It’s easier to ask forgiveness than permission". Which usually means writing code that assumes everything is fine, but then wrapping it with a try...except block to handle things—just in case—it’s not.

Here’s that coding style applied to your problem:

try:
    my_value = int(my_value)
except TypeError:
    my_value = 0  # or whatever you want to do

answer = my_value / divisor

Or perhaps the even simpler and slightly faster:

try:
    answer = int(my_value) / divisor
except TypeError:
    answer = 0

The inverse and more traditional approach is known as LBYL which stands for "Look before you leap" is what @Soviut and some of the others have suggested. For additional coverage of this topic see my answer and associated comments to the question Determine whether a key is present in a dictionary elsewhere on this site.

One potential problem with EAFP is that it can hide the fact that something is wrong with some other part of your code or third-party module you’re using, especially when the exceptions frequently occur (and therefore aren’t really "exceptional" cases at all).

I was having the same problem using the python email functions.
Below is the code I was trying to retrieve email subject into a variable. This works fine for most emails and the variable populates. If you receive an email from Yahoo or the like and the sender did no fill out the subject line Yahoo does not create a subject line in the email and you get a NoneType returned from the function. Martineau provided a correct answer as well as Soviut. IMO Soviut’s answer is more concise from a programming stand point; not necessarily from a Python one.
Here is some code to show the technique:

import sys, email, email.Utils 

afile = open(sys.argv[1], 'r')    
m = email.message_from_file(afile)    
subject = m["subject"]

# Soviut's Concise test for unset variable.

if subject is None:    
     subject = "[NO SUBJECT]"

# Alternative way to test for No Subject created in email (Thanks for NoneThing Yahoo!)

try:    
    if len(subject) == 0:    
        subject = "[NO SUBJECT]"

except TypeError:    
    subject = "[NO SUBJECT]"

print subject

afile.close()

I’ve successfully used int(x or 0) for this type of error, so long as None should equate to 0 in the logic.
Note that this will also resolve to 0 in other cases where testing x returns False. e.g. empty list, set, dictionary or zero length string.
Sorry, Kindall already gave this answer.

In some situations it is helpful to have a function to convert None to int zero:

def nz(value):

    '''
    Convert None to int zero else return value.
    '''

    if value == None:
        return 0
    return value

In Python 3 you can use the “or” keyword too. This way:

foo = bar or 0
foo2 = bar or ""

SUMMARY:
Transform the NoneType item to String type_ And then from String type to Integer type_

CODE (researching):

bdate = input("What is your birth date in 
YYYY/MM/DD: ")
def cat(bdate):
    def out(bdate):  
        fdate = (bdate[0:4])
        # splits a String into its component 
        Letters  //Python
        s = print(*fdate)
        print(type(s))
        x = str(s)
        print(type(x))
        ad = "AD"
        print(len(ad))
        return fdate
return out
c = cat(bdate)  
c(bdate)