Changing strings into integers

Question

I’m going crazy and I can not figure the right solution 🙁

How can I solve that problems. I have a loop and I can get diffrent types like:

empty string
10
10K
2.3K
2.34K
2M
2.2M
2.23M

I need to change them into numbers:

Asked By: Anna K

||

Source

Answer 1

Your steps should be:

check if string is empty
- return 0
check if string ends in K or M
- if it does, strip that character off the end, store it for later
- multiply by appropriate factor (K = 1000 or M = 1000000)

This can be achieved with the following:

def convert(value):
    if value:
        # determine multiplier
        multiplier = 1
        if value.endswith('K'):
            multiplier = 1000
            value = value[0:len(value)-1] # strip multiplier character
        elif value.endswith('M'):
            multiplier = 1000000
            value = value[0:len(value)-1] # strip multiplier character

        # convert value to float, multiply, then convert the result to int
        return int(float(value) * multiplier)

    else:
        return 0

values = [
    '',
    '10',
    '10K',
    '2.3K',
    '2.34K',
    '2M',
    '2.2M',
    '2.23M',
]

# use a list comprehension to call the function on all values
numbers = [convert(value) for value in values]

print numbers

This should return

[0, 10, 10000, 2300, 2340, 2000000, 2200000, 2230000]

Answered By: Soviut

Answer 2

A quick hack to get the floats:

In [15]: powers = {'K': 10 ** 3, 'M': 10 ** 6}

In [16]: def f(s):
    ...:     try:
    ...:         if s[-1] in powers.keys():
    ...:            return float(s[:-1]) * powers[s[-1]]
    ...:         else:
    ...:            return float(s)
    ...:     except:
    ...:         return s
    ...:         

In [17]: map(f, ['', '10', '10K', '2.3K', '2.34K', '2M', '2.2M', '2.23M'])
Out[17]: ['', 10.0, 10000.0, 2300.0, 2340.0, 2000000.0, 2200000.0, 2230000.0]

Answered By: Nehal J Wani

Answer 3

I agree with other answers, this solution will be best to solve it without Regular Expression.

But, if you still want to use regex, here is a nice way to do this using JavaScript (sorry, not familiar with Python):

var new_arr = ['','10','10K','2.3K','2.34K','2M','2.2M','2.23M'].map(function(value) {
    return value.replace(/^(d*(?:.d+)?)([kgm]?)$/i, function(_, number, group) {
        return !group && (number||'0') || parseFloat(number) * Math.pow(10, {'k':3,'m':6,'g':9}[group.toLowerCase()]);
    });
});

If someone could translate it to Python, it would be best (and it will teach me a bit of Python well). :))

Answered By: Slavik Meltser

Answer 4

import re

def transform_value(value):
    match = re.match(r'^(d*(?:.d+)?)([kgm]?)$', value, re.IGNORECASE)
    if match:
        number = match.group(1) or '0'
        group = match.group(2).lower()
        if group:
            return int(float(number) * 10**{'k': 3, 'm': 6, 'g': 9}[group])
        return int(number)
    return 0

new_arr = [transform_value(value) for value in 
['','10','10K','2.3K','2.34K','2M','2.2M','2.23M']]

print(new_arr)

output

[0, 10, 10000, 2300, 2340, 2000000, 2200000, 2230000]

Answered By: Mohit

Changing strings into integers

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