How to use tplquad?

Question:

I try to integrate this :

integrate(integrate(integrate(2*sin(z)*cos(atan((2*cos(y)-0.5+x)/(2*sin(y)))),y,0,pi/2),x,0,1),z,0,pi/2);

Wolfram find the solution but I would like to control the accuracy. I try with tplquad but there is some error.

def f(x,y,z):
return  2*sin(z)*cos(atan((2*cos(y)-0.5+x)/(2*sin(y))))

tplquad(f,0,1,0,pi/2,0,pi/2)

The errors are:

Blockquote
File “”, line 3, in
File “/usr/lib/python2.7/dist-packages/scipy/integrate/quadpack.py”, line 526, in tplquad
return dblquad(_infunc2,a,b,gfun,hfun,(func,qfun,rfun,args),epsabs=epsabs,epsrel=epsrel)
File “/usr/lib/python2.7/dist-packages/scipy/integrate/quadpack.py”, line 461, in dblquad
return quad(_infunc,a,b,(func,gfun,hfun,args),epsabs=epsabs,epsrel=epsrel)
File “/usr/lib/python2.7/dist-packages/scipy/integrate/quadpack.py”, line 281, in quad
retval = _quad(func,a,b,args,full_output,epsabs,epsrel,limit,points)
File “/usr/lib/python2.7/dist-packages/scipy/integrate/quadpack.py”, line 345, in _quad
return _quadpack._qagse(func,a,b,args,full_output,epsabs,epsrel,limit)
File “/usr/lib/python2.7/dist-packages/scipy/integrate/quadpack.py”, line 406, in _infunc
a = gfun(x)

Have you an idea where the error could come from ?

Asked By: mp de sousa

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Answers:

The documentation of tplquad states that the integration limits of the inner integrals should be provided as functions of the outer integration variables (even if they happen to be constants as in your case).

The correct usage of tplquad in your case is shown below. Note that the ordering of the arguments in the definition of f should correspond to the ordering of integrations. The first (last) argument of f is the last (first) to be integrated. In this case the ordering is irrelevant due to fixed integration limits.

import numpy as np
from scipy.integrate import tplquad

def f(y,x,z):
    return  2*np.sin(z)*np.cos(np.arctan((2*np.cos(y)-0.5+x)/(2*np.sin(y))))

tplquad(f,0,np.pi/2, lambda z: 0, lambda z:1, lambda z, x: 0, lambda z, x: np.pi/2)

(1.9999999999999998, 2.492629060475153e-14)

Answered By: Stelios