How to get everything from the list except the first element using list slicing
Question:
So I have something that I am parsing, however here is an example of what I would like to do:
list = ['A', 'B', 'C']
And using list slicing have it return to me everything but the first index. So in this case:
['B', 'C']
I have been messing with stuff like list[:-1], list[::-1], list[0:-1], etc. But I can’t seem to be able to find this out.
What I am actual doing is:
* I have a error message that has a error code in the beginning such as:
['226', 'Transfer', 'Complete']
and I want to just display Transfer Complete on a popup widget. Of course I am casting to a string.
Thank you for all help, and if answer differs via Python 2.7.x and Python 3.x.x Please answer for both versions.
Thanks, looked a lot around stackoverflow and python tutorials couldn’t really quite get what I was looking for. Thanks for your help!
Answers:
You can just do [1:].
This will work on both versions.
It can be done like this:
list[1:]
So I have something that I am parsing, however here is an example of what I would like to do:
list = ['A', 'B', 'C']
And using list slicing have it return to me everything but the first index. So in this case:
['B', 'C']
I have been messing with stuff like list[:-1], list[::-1], list[0:-1], etc. But I can’t seem to be able to find this out.
What I am actual doing is:
* I have a error message that has a error code in the beginning such as:
['226', 'Transfer', 'Complete']
and I want to just display Transfer Complete on a popup widget. Of course I am casting to a string.
Thank you for all help, and if answer differs via Python 2.7.x and Python 3.x.x Please answer for both versions.
Thanks, looked a lot around stackoverflow and python tutorials couldn’t really quite get what I was looking for. Thanks for your help!
You can just do [1:].
This will work on both versions.
It can be done like this:
list[1:]