Python Sendgrid send email with PDF attachment file

Question:

I’m trying to attach a PDF file to my email sent with sendgrid.

Here is my code :

sg = sendgrid.SendGridAPIClient(apikey=os.environ.get('SENDGRID_API_KEY'))

from_email = Email("[email protected]")
subject = "subject"
to_email = Email("[email protected]")
content = Content("text/html", email_body)

pdf = open(pdf_path, "rb").read().encode("base64")
attachment = Attachment()
attachment.set_content(pdf)
attachment.set_type("application/pdf")
attachment.set_filename("test.pdf")
attachment.set_disposition("attachment")
attachment.set_content_id(number)

mail = Mail(from_email, subject, to_email, content)
mail.add_attachment(attachment)

response = sg.client.mail.send.post(request_body=mail.get())

print(response.status_code)
print(response.body)
print(response.headers)

But the Sendgrid Python library is throwing an error HTTP Error 400: Bad Request.

What is wrong with my code ?

Asked By: John

||

Answers:

I found a solution. I replaced this line :

pdf = open(pdf_path, "rb").read().encode("base64")

By this :

with open(pdf_path, 'rb') as f:
    data = f.read()

encoded = base64.b64encode(data)

Now it works. I can send encoded file in the set_content :

attachment.set_content(encoded)

Note: The answer above works for Sendgrid v2 or lower. For v3 and up use:

encoded = base64.b64encode(data).decode()
Answered By: John

This is my solution, Works with Sendgrid V3

    # Where it was uploaded Path.
    file_path = "MY_FILE_PATH"

    with open(file_path, 'rb') as f:
        data = f.read()

    # Encode contents of file as Base 64
    encoded = base64.b64encode(data).decode()

    """Build attachment"""
    attachment = Attachment()
    attachment.content = encoded
    attachment.type = "application/pdf"
    attachment.filename = "my_pdf_attachment.pdf"
    attachment.disposition = "attachment"
    attachment.content_id = "PDF Document file"

    sg = sendgrid.SendGridAPIClient(apikey=settings.SENDGRID_API_KEY)

    from_email = Email("[email protected]")
    to_email = Email('[email protected]')
    content = Content("text/html", html_content)

    mail = Mail(from_email, 'Attachment mail PDF', to_email, content)
    mail.add_attachment(attachment)

    try:
        response = sg.client.mail.send.post(request_body=mail.get())
    except urllib.HTTPError as e:
        print(e.read())
        exit()
Answered By: Eddwin Paz

Straight from the Sendgrid docs:

import urllib.request as urllib
import base64
import os
import json
from sendgrid import SendGridAPIClient
from sendgrid.helpers.mail import (Mail, Attachment, FileContent, FileName, FileType, Disposition, ContentId)

import os
import json
from sendgrid import SendGridAPIClient
from sendgrid.helpers.mail import Mail

message = Mail(
    from_email='[email protected]',
    to_emails='[email protected]',
    subject='Sending with Twilio SendGrid is Fun',
    html_content='<strong>and easy to do anywhere, even with Python</strong>')
file_path = 'example.pdf'
with open(file_path, 'rb') as f:
    data = f.read()
encoded = base64.b64encode(data).decode()
attachment = Attachment()
attachment.file_content = FileContent(encoded)
attachment.file_type = FileType('application/pdf')
attachment.file_name = FileName('test_filename.pdf')
attachment.disposition = Disposition('attachment')
attachment.content_id = ContentId('Example Content ID')
message.attachment = attachment
try:
    sendgrid_client = SendGridAPIClient(os.environ.get('SENDGRID_API_KEY'))
    response = sendgrid_client.send(message)
    print(response.status_code)
    print(response.body)
    print(response.headers)
except Exception as e:
    print(e.message)
Answered By: John R Perry

"How does one attach more than one file to a message?"

Build additional attachments:

file_path = 'test_filename1.pdf'
with open(file_path, 'rb') as f:
    data = f.read()
    f.close()
encoded = base64.b64encode(data).decode()
attachment1 = Attachment()
attachment1.file_content = FileContent(encoded)
attachment1.file_type = FileType('application/pdf')
attachment1.file_name = FileName('test_filename1.pdf')
attachment1.disposition = Disposition('attachment')
attachment1.content_id = ContentId('Example Content ID1')

file_path = 'test_filename2.pdf'
with open(file_path, 'rb') as f:
    data = f.read()
    f.close()
encoded = base64.b64encode(data).decode()
attachment2 = Attachment()
attachment2.file_content = FileContent(encoded)
attachment2.file_type = FileType('application/pdf')
attachment2.file_name = FileName('test_filename2.pdf')
attachment2.disposition = Disposition('attachment')
attachment2.content_id = ContentId('Example Content ID2')

mail.attachment = [attachment1,attachment2]
Answered By: amar

The following approach works for me:

    mail = Mail(
        from_email=SendgridEmail(from_email_str),
        to_emails=[To(e) for e in to_emails],
        subject=email_subject,
        html_content=HtmlContent(email_html_content)
    )
    attachment = Attachment(
        file_content=file_content_b64_encoded,
        file_name=filename,
        file_type=file_type,
        disposition='attachment',
        content_id=filename
    )
    mail.add_attachment(attachment)
Answered By: Evgenii