Remove an item in list and get a new list?
Question:
I saw there are several topics on removing items from a list, including using remove(), pop(), and del. But none of these is what I am looking for, since I want to get a new list when the items are removed. For example, I want to do this:
a = [1, 2, 3, 4, 5, 6]
<fill in > # This step somehow removes the third item and get a new list b and let
b = [1, 2, 4, 5, 6]
How can I do this?
Answers:
If you want to have a new list without the third element then:
b = a[:2] + a[3:]
If you want a list without value ‘3’:
b = [n for n in a if n != 3]
I saw there are several topics on removing items from a list, including using remove(), pop(), and del. But none of these is what I am looking for, since I want to get a new list when the items are removed. For example, I want to do this:
a = [1, 2, 3, 4, 5, 6]
<fill in > # This step somehow removes the third item and get a new list b and let
b = [1, 2, 4, 5, 6]
How can I do this?
If you want to have a new list without the third element then:
b = a[:2] + a[3:]
If you want a list without value ‘3’:
b = [n for n in a if n != 3]