How to write Python if else in single line?

Question

category.is_parent = True if self.request.get('parentKey') is not None else category.is_parent = False

Above is the code in which I am trying to write a if else in a single line and it is giving me this syntax error

SyntaxError: can't assign to conditional expression"

But if I write it in following way it works fine

if self.request.get('parentKey') is not None:
     category.is_parent = True
else:
    category.is_parent = False

Asked By: Saim Abdullah

||

Source

Answer 1

Try this:

category.is_parent = True if self.request.get('parentKey') else False

To check only against None:

category.is_parent = True if self.request.get('parentKey') is not None else False

Answered By: ettanany

Answer 2

You can write:

category.is_parent = True if self.request.get('parentKey') is not None else False

Or even simpler in this case:

category.is_parent = self.request.get('parentKey') is not None

Answered By: grepcake

Answer 3

You can write this with a one liner but using the [][] python conditional syntax. Like so:

category.is_parent = [False,True][self.request.get('parentKey') is not None

The first element in the first array is the result for the else part of the condition and the second element is the result when the condition in the second array evaluates to True.

Answered By: Kofi Nartey

How to write Python if else in single line?

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