How to get xml format in Django Rest Framework
Question:
I’m trying to get xml format in Django Rest FrameWork,I tried the tutorial provided by Django Rest Framework, I’m new to django, I did the following.
settings.py
INSTALLED_APPS = [
'django.contrib.admin',
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.messages',
'django.contrib.staticfiles',
'rest_framework',
'books',
'users',
]
urls.py
from django.conf.urls import url
from django.contrib import admin
from books.views import *
from users.views import *
from rest_framework.urlpatterns import format_suffix_patterns
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^books/all/$', all_books),
url(r'^user/', get_user)
]
urlpatterns = format_suffix_patterns(urlpatterns, allowed=['json', 'html','xml'])
views.py
from rest_framework.response import Response
from rest_framework.decorators import api_view
from books.serializers import *
from books.models import *
# Create your views here.
@api_view(['GET'])
def all_books(request):
books = Book.objects.all()
serializers = BookSerializer(books,many=True)
return Response(serializers.data)
When I try to access the xml data, I Get this error by doing ?format=xml
{"detail":"Not found."}
the tutorial link http://www.django-rest-framework.org/api-guide/format-suffixes/
Answers:
Actually your settings.py
is missing the xml parser config.
- install rest_framework_xml :
pip install djangorestframework-xml
- Update INSTALLED_APPS in settings.py
INSTALLED_APPS = [
'django.contrib.admin',
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.messages',
'django.contrib.staticfiles',
'rest_framework',
'rest_framework_xml',
'books',
'users',
]
- Add xml parser in settings.py:
REST_FRAMEWORK = {
'DEFAULT_PARSER_CLASSES': (
'rest_framework_xml.parsers.XMLParser',
),
'DEFAULT_RENDERER_CLASSES': (
'rest_framework_xml.renderers.XMLRenderer',
),
}
It is adviceable that you use virtual environment. Check how to use pipenv here
I’m trying to get xml format in Django Rest FrameWork,I tried the tutorial provided by Django Rest Framework, I’m new to django, I did the following.
settings.py
INSTALLED_APPS = [
'django.contrib.admin',
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.messages',
'django.contrib.staticfiles',
'rest_framework',
'books',
'users',
]
urls.py
from django.conf.urls import url
from django.contrib import admin
from books.views import *
from users.views import *
from rest_framework.urlpatterns import format_suffix_patterns
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^books/all/$', all_books),
url(r'^user/', get_user)
]
urlpatterns = format_suffix_patterns(urlpatterns, allowed=['json', 'html','xml'])
views.py
from rest_framework.response import Response
from rest_framework.decorators import api_view
from books.serializers import *
from books.models import *
# Create your views here.
@api_view(['GET'])
def all_books(request):
books = Book.objects.all()
serializers = BookSerializer(books,many=True)
return Response(serializers.data)
When I try to access the xml data, I Get this error by doing ?format=xml
{"detail":"Not found."}
the tutorial link http://www.django-rest-framework.org/api-guide/format-suffixes/
Actually your settings.py
is missing the xml parser config.
- install rest_framework_xml :
pip install djangorestframework-xml
- Update INSTALLED_APPS in settings.py
INSTALLED_APPS = [
'django.contrib.admin',
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.messages',
'django.contrib.staticfiles',
'rest_framework',
'rest_framework_xml',
'books',
'users',
]
- Add xml parser in settings.py:
REST_FRAMEWORK = {
'DEFAULT_PARSER_CLASSES': (
'rest_framework_xml.parsers.XMLParser',
),
'DEFAULT_RENDERER_CLASSES': (
'rest_framework_xml.renderers.XMLRenderer',
),
}
It is adviceable that you use virtual environment. Check how to use pipenv here