spark 2.1.0 session config settings (pyspark)

Question

I am trying to overwrite the spark session/spark context default configs, but it is picking entire node/cluster resource.

 spark  = SparkSession.builder
                      .master("ip")
                      .enableHiveSupport()
                      .getOrCreate()

 spark.conf.set("spark.executor.memory", '8g')
 spark.conf.set('spark.executor.cores', '3')
 spark.conf.set('spark.cores.max', '3')
 spark.conf.set("spark.driver.memory",'8g')
 sc = spark.sparkContext

It works fine when i put the configuration in spark submit

spark-submit --master ip --executor-cores=3 --diver 10G code.py

Asked By: Harish

||

Source

Answer 1

You aren’t actually overwriting anything with this code. Just so you can see for yourself try the following.

As soon as you start pyspark shell type:

sc.getConf().getAll()

This will show you all of the current config settings. Then try your code and do it again. Nothing changes.

What you should do instead is create a new configuration and use that to create a SparkContext. Do it like this:

conf = pyspark.SparkConf().setAll([('spark.executor.memory', '8g'), ('spark.executor.cores', '3'), ('spark.cores.max', '3'), ('spark.driver.memory','8g')])
sc.stop()
sc = pyspark.SparkContext(conf=conf)

Then you can check yourself just like above with:

sc.getConf().getAll()

This should reflect the configuration you wanted.

Answered By: Grr

Answer 2

update configuration in Spark 2.3.1

To change the default spark configurations you can follow these steps:

Import the required classes

from pyspark.conf import SparkConf
from pyspark.sql import SparkSession

Get the default configurations

spark.sparkContext._conf.getAll()

Update the default configurations

conf = spark.sparkContext._conf.setAll([('spark.executor.memory', '4g'), ('spark.app.name', 'Spark Updated Conf'), ('spark.executor.cores', '4'), ('spark.cores.max', '4'), ('spark.driver.memory','4g')])

Stop the current Spark Session

spark.sparkContext.stop()

Create a Spark Session

spark = SparkSession.builder.config(conf=conf).getOrCreate()

Answered By: bob

Answer 3

Setting ‘spark.driver.host’ to ‘localhost’ in the config works for me

spark = SparkSession 
    .builder 
    .appName("MyApp") 
    .config("spark.driver.host", "localhost") 
    .getOrCreate()

Answered By: Vivek

Answer 4

You could also set configuration when you start pyspark, just like spark-submit:

pyspark --conf property=value

Here is one example

-bash-4.2$ pyspark
Python 3.6.8 (default, Apr 25 2019, 21:02:35) 
[GCC 4.8.5 20150623 (Red Hat 4.8.5-36)] on linux
Welcome to
      ____              __
     / __/__  ___ _____/ /__
    _ / _ / _ `/ __/  '_/
   /__ / .__/_,_/_/ /_/_   version 2.4.0-cdh6.2.0
      /_/

Using Python version 3.6.8 (default, Apr 25 2019 21:02:35)
SparkSession available as 'spark'.
>>> spark.conf.get('spark.eventLog.enabled')
'true'
>>> exit()


-bash-4.2$ pyspark --conf spark.eventLog.enabled=false
Python 3.6.8 (default, Apr 25 2019, 21:02:35) 
[GCC 4.8.5 20150623 (Red Hat 4.8.5-36)] on linux
Welcome to
      ____              __
     / __/__  ___ _____/ /__
    _ / _ / _ `/ __/  '_/
   /__ / .__/_,_/_/ /_/_   version 2.4.0-cdh6.2.0
      /_/

Using Python version 3.6.8 (default, Apr 25 2019 21:02:35)
SparkSession available as 'spark'.
>>> spark.conf.get('spark.eventLog.enabled')
'false'

Answered By: user3282611

Answer 5

I had a very different requirement where I had to check if I am getting parameters of executor and driver memory size and if getting, had to replace config with only changes in executer and driver. Below are the steps:

Import Libraries

from pyspark.conf import SparkConf
from pyspark.sql import SparkSession

Define Spark and get the default configuration

spark = (SparkSession.builder
        .master("yarn")
        .appName("experiment") 
        .config("spark.hadoop.fs.s3a.multiobjectdelete.enable", "false")
        .getOrCreate())

conf = spark.sparkContext._conf.getAll()

Check if executor and driver size exists (I am giving here pseudo code 1 conditional check, rest you can create cases) then use the given configuration based on params or skip to the default configuration.

if executor_mem is not None and driver_mem  is not None:
    conf = spark.sparkContext._conf.setAll([('spark.executor.memory',executor_mem),('spark.driver.memory',driver_mem)])
    spark.sparkContext.stop()
    spark = SparkSession.builder.config(conf=conf).getOrCreate()
else:
    spark = spark

Don’t forget to stop spark context, this will make sure executor and driver memory size have differed as you passed in params. Hope this helps!

Answered By: Hari_pb

Answer 6

I know this is little old post and have some already accepted ans, but I just wanted to post a working code for the same.

from pyspark.sql import SparkSession

spark = SparkSession 
    .builder 
    .appName("MyApp") 
    .config("spark.driver.host", "localhost") 
    .getOrCreate()

default_conf = spark.sparkContext._conf.getAll()
print(default_conf)

conf = spark.sparkContext._conf.setAll([('spark.executor.memory', '4g'),
                                        ('spark.app.name', 'Spark Updated Conf'),
                                        ('spark.executor.cores', '4'),
                                        ('spark.cores.max', '4'),
                                        ('spark.driver.memory','4g')])

spark.sparkContext.stop()

spark = SparkSession 
    .builder 
    .appName("MyApp") 
    .config(conf=conf) 
    .getOrCreate()


default_conf = spark.sparkContext._conf.get("spark.cores.max")
print("updated configs " , default_conf)

Answered By: Suman Banerjee

spark 2.1.0 session config settings (pyspark)

Question:

Answers: