Python : Remove all values from a list in between two values
Question:
I have a list of string values.
list1 = ["13:00","13:10","13:20","13:30","13:40"]
range_start = "13:10"
range_end = "13:30"
I want to remove all values (including range_start and range_end)that lie in between the ranges.
Answers:
EDIT:
Sorry, misread your question. I thought you only wanted to keep these values. Changed my code accordingly.
list1 = ["13:00","13:10","13:20","13:30","13:40"]
range_start = "13:10"
range_end = "13:30"
You can use list comprehension with the range condition:
list1 = [x for x in list1 if not(range_start<=x<=range_end)]
print(list1)
You could also use filter on your list:
list1=list(filter(lambda x:not(range_start<=x<=range_end), list1))
print(list1)
list1 = ["13:00","13:10","13:20","13:30","13:40"]
del list1[1:-1]
print(list1)
I have a list of string values.
list1 = ["13:00","13:10","13:20","13:30","13:40"]
range_start = "13:10"
range_end = "13:30"
I want to remove all values (including range_start and range_end)that lie in between the ranges.
EDIT:
Sorry, misread your question. I thought you only wanted to keep these values. Changed my code accordingly.
list1 = ["13:00","13:10","13:20","13:30","13:40"]
range_start = "13:10"
range_end = "13:30"
You can use list comprehension with the range condition:
list1 = [x for x in list1 if not(range_start<=x<=range_end)]
print(list1)
You could also use filter on your list:
list1=list(filter(lambda x:not(range_start<=x<=range_end), list1))
print(list1)
list1 = ["13:00","13:10","13:20","13:30","13:40"]
del list1[1:-1]
print(list1)