How do I round down an epoch timestamp to the nearest minute in Python?

Question

I’d like to round down/floor an epoch/Unix timestamp so as to remove the seconds.

I’m using Python 2.x and Python 3.x

E.g.

1488728901 = Sun, 05 Mar 2017 15:48:21 GMT

to:

1488728880 = Sun, 05 Mar 2017 15:48:00 GMT

There’s some great answers by using datetime to manipulate the time but it seems OTT if my input and output are integers.

Asked By: Alastair McCormack

||

Source

Answer 1

A simple bit of maths:

int(timestamp//60 * 60)

(// replicates Python 2.x division (/) where the result is a whole number)

Answered By: Alastair McCormack

Answer 2

Or if you’re not clever you could use arrow:

>>> import arrow
>>> timestamp = arrow.get(1488728901)
>>> timestamp
<Arrow [2017-03-05T15:48:21+00:00]>
>>> timestamp = timestamp.floor('minute')
>>> timestamp.format('YYYY-MMM-DD HH:mm:ss')
'2017-Mar-05 15:48:00'

Answered By: Bill Bell

Answer 3

you can do one thing here lets suppose col has your unix value. modified_value=((col+30*1000)/60*1000).cast("long") — it will be decimal or integer covert it into proper integer if

modified_value_final = modified_value*60*1000

Example val=1488728901
modifeid_value=(1488728901+30000)/60000 = 24,812.64835
modified_value = 24,812 --after casting to long
final_modified_value = 24812*60000=1,488,720,000

Answered By: Robin Singh Barala

How do I round down an epoch timestamp to the nearest minute in Python?

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