Optional[Type[Foo]] raises TypeError in Python 3.5.2

Question

This code:

#!/usr/bin/env python

from typing import Optional, Type

class Foo(object):
    pass

class Bar(Foo):
    pass

def test_me() -> Optional[Type[Foo]]:
    print("Hi there!")
    return Bar

if __name__ == "__main__":
    test_me()

will raise TypeError on 3.5.2:

Traceback (most recent call last):
  File "./test.py", line 11, in <module>
    def test_me() -> Optional[Type[Foo]]:
  File "/Users/mnot/.pyenv/versions/3.5.2/lib/python3.5/typing.py", line 649, in __getitem__
return Union[arg, type(None)]
  File "/Users/mnot/.pyenv/versions/3.5.2/lib/python3.5/typing.py", line 552, in __getitem__
dict(self.__dict__), parameters, _root=True)
  File "/Users/mnot/.pyenv/versions/3.5.2/lib/python3.5/typing.py", line 512, in __new__
for t2 in all_params - {t1} if not isinstance(t2, TypeVar)):
  File "/Users/mnot/.pyenv/versions/3.5.2/lib/python3.5/typing.py", line 512, in <genexpr>
for t2 in all_params - {t1} if not isinstance(t2, TypeVar)):
  File "/Users/mnot/.pyenv/versions/3.5.2/lib/python3.5/typing.py", line 1077, in __subclasscheck__
if super().__subclasscheck__(cls):
  File "/Users/mnot/.pyenv/versions/3.5.2/lib/python3.5/abc.py", line 225, in __subclasscheck__
for scls in cls.__subclasses__():
TypeError: descriptor '__subclasses__' of 'type' object needs an argument

whereas it runs fine on 3.6. Same problem if I spell out Optional as Union[None, Type[Foo]].

Is there any workaround for 3.5.2, while still accurately annotating the return type?

Asked By: Mark Nottingham

||

Source

Answer 1

This is a bug in Python 3.5.2.

Optional[cls] is a wrapper for Union[cls, type(None)], which uses __subclasses__() to establish whether one class is a subclass of another.

However, Type is a subclass of type in Python 3.5.2, which means that

Union[Type[anything], anything_else]

will eventually call

type.__subclasses__()

… which is a problem, because type is a metaclass, and so expects to be called with the class whose subclasses are being sought, in exactly the same way that calling an instance method on a regular class requires you to supply an instance of itself, e.g. str.upper('foo').

The problem is fixed in Python 3.5.3 (and, as you’ve noticed, 3.6) by making Type no longer a subclass of type.

Answered By: Zero Piraeus

Answer 2

Thx Zero Piraeus

i had same problem i ve using python 3.5.2
i ve edit
usr/lib/python3.5/typing.py file

class Type(type, Generic[CT_co], extra=type):

CHANGED TO

class Type(Generic[CT_co], extra=type):

then it fixed …

Answered By: seint

Answer 3

I had a same issue on python 3.5.2

I just installed the lower version of pandas

pandas==0.24.2

Default installed version was

pandas==0.25.1

Hope this help.

Answered By: Sid

Optional[Type[Foo]] raises TypeError in Python 3.5.2

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