Iterate over Worksheets, Rows, Columns

Question

I want to print all data (all rows) of a specific column in python using openpyxl I am working in this way;

from openpyxl import load_workbook
workbook = load_workbook('----------/dataset.xlsx')
sheet = workbook.active  
for i in sheet:
   print(sheet.cell(row=i, column=2).value)

But it gives

if row < 1 or column < 1:
TypeError: unorderable types: tuple() < int()

Because i am iterating in row=i. If I use sheet.cell(row=4, column=2).value it print the value of cell. But how can I iterate over all document?

Edit 1

On some research, it is found that data can be get using Sheet Name. The Sheet 1 exists in the .xlsx file but its data is not printing. Any problem in this code?

workbook = load_workbook('---------------/dataset.xlsx')
print(workbook.get_sheet_names())
worksheet =workbook.get_sheet_by_name('Sheet1')
c=2
for i in worksheet: 
    d = worksheet.cell(row=c, column=2)
    if(d.value is None):
        return
    else:
        print(d.value)
    c=c+1

Asked By: Humty

||

Source

Answer 1

Try this,

from openpyxl import load_workbook
workbook = load_workbook('----------/dataset.xlsx')
sheet = workbook.active
row_count = sheet.max_row
for i in range(row_count):
   print(sheet.cell(row=i, column=2).value)

Answered By: Chanda Korat

Answer 2

Read the OpenPyXL Documentation

Iteration over all worksheets in a workbook, for instance:

for n, sheet in enumerate(wb.worksheets):
    print('Sheet Index:[{}], Title:{}'.format(n, sheet.title))

Output:

Sheet Index:[0], Title: Sheet    
Sheet Index:[1], Title: Sheet1    
Sheet Index:[2], Title: Sheet2

Iteration over all rows and columns in one Worksheet:

worksheet = workbook.get_sheet_by_name('Sheet')

for row_cells in worksheet.iter_rows():
    for cell in row_cells:
       print('%s: cell.value=%s' % (cell, cell.value) )

Output:

<Cell Sheet.A1>: cell.value=²234
<Cell Sheet.B1>: cell.value=12.5
<Cell Sheet.C1>: cell.value=C1
<Cell Sheet.D1>: cell.value=D1
<Cell Sheet.A2>: cell.value=1234
<Cell Sheet.B2>: cell.value=8.2
<Cell Sheet.C2>: cell.value=C2
<Cell Sheet.D2>: cell.value=D2

Iteration over all columns of one row, for instance row==2:

for row_cells in worksheet.iter_rows(min_row=2, max_row=2):
    for cell in row_cells:
        print('%s: cell.value=%s' % (cell, cell.value) )

Output:

<Cell Sheet.A2>: cell.value=1234  
<Cell Sheet.B2>: cell.value=8.2  
<Cell Sheet.C2>: cell.value=C2  
<Cell Sheet.D2>: cell.value=D2

Iteration over all rows, only column 2:

for col_cells in worksheet.iter_cols(min_col=2, max_col=2):
    for cell in col_cells:
        print('%s: cell.value=%s' % (cell, cell.value))

Output:

<Cell Sheet.B1>: cell.value=12.5
<Cell Sheet.B2>: cell.value=8.2
<Cell Sheet.B3>: cell.value=9.8
<Cell Sheet.B4>: cell.value=10.1
<Cell Sheet.B5>: cell.value=7.7

Tested with Python:3.4.2 – openpyxl:2.4.1 – LibreOffice: 4.3.3.2

Answered By: stovfl

Answer 3

This code will read a sheet as if it was a CSV and populate a list of dictionaries in result using the first row as the column titles.

        from openpyxl import load_workbook

        result = []
        wb = load_workbook(filename=file_name)
        sheet = wb.active
        col_count = sheet.max_column
        column_names = {}
        for c in range(1, col_count):
            heading = sheet.cell(row=1, column=c).value
            if not heading:
                col_count = c
                break
            column_names[c] = heading

        for r, row_cells in enumerate(sheet.iter_rows(2), 2):
            row = {}
            for c in range(1, col_count):
                value = sheet.cell(row=r, column=c).value
                if type(value) == datetime:
                    value = value.strftime('%Y-%m-%d')
                row[column_names[c]] = value
            result.append(row)

Answered By: Martlark

Iterate over Worksheets, Rows, Columns

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