Remove duplicates key from list of dictionaries python

Question

I am trying to remove the duplicates from following list:

distinct_cur = [
    {'rtc': 0, 'vf': 0, 'mtc': 0, 'doc': 'good job', 'foc': 195, 'st': 0.0, 'htc': 2, '_id': ObjectId('58e86a550a0aeff4e14ca6bb'), 'ftc': 0}, 
    {'rtc': 0, 'vf': 0, 'mtc': 0, 'doc': 'good job', 'foc': 454, 'st': 0.8, 'htc': 1, '_id': ObjectId('58e8d03958ae6d179c2b4413'), 'ftc': 1},
    {'rtc': 0, 'vf': 2, 'mtc': 1, 'doc': 'test', 'foc': 45, 'st': 0.8, 'htc': 12, '_id': ObjectId('58e8d03958ae6d180c2b4446'), 'ftc': 0}
]

Of dictionaries based on condition that if ‘doc’ key value text is same then one of the dictionary should be removed. I have tried the following solution:

distinct_cur = [dict(y) for y in set(tuple(x.items()) for x in cur)]

But duplicates are still present in the final list.

Below is the desired output as in 1st and 2nd distinct_cur text of key ‘doc’ value is same (good job):

[
    {'rtc': 0, 'vf': 0, 'mtc': 0, 'doc': 'good job', 'foc': 195, 'st': 0.0, 'htc': 2, '_id': ObjectId('58e86a550a0aeff4e14ca6bb'), 'ftc': 0}, 
    {'rtc': 0, 'vf': 2, 'mtc': 1, 'doc': 'test', 'foc': 45, 'st': 0.8, 'htc': 12, '_id': ObjectId('58e8d03958ae6d180c2b4446'), 'ftc': 0}
]

Asked By: shanky

||

Source

Answer 1

You’re creating a set out of different elements and expect that it will remove the duplicates based on a criterion that only you know.

You have to iterate through your list, and add to the result list only if doc has a different value than the previous ones:
for instance like this:

done = set()
result = []
for d in distinct_cur:
    if d['doc'] not in done:
        done.add(d['doc'])  # note it down for further iterations
        result.append(d)

that will keep only the first occurrence(s) of the dictionaries which have the same doc key by registering the known keys in an auxiliary set.

Another possibility is to use a dictionary with the key as the "doc" key of the dictionary, iterating backwards in the list so the first items overwrite the last ones in the list:

result = list({i['doc']:i for i in reversed(distinct_cur)}.values())

Answered By: Jean-François Fabre

Answer 2

Try this:

distinct_cur  =[dict(t) for t in set([tuple(d.items()) for d in distinct_cur])]

Worked for me…

Answered By: Yuval Pruss

Answer 3

I see 2 similar solutions that depend on your domain problem: do you want to keep the first instance of a key or the last instance?

Using the last (so as to overwrite the previous matches) is simpler:

d = {r['doc']: r for r in distinct_cur}.values()

Answered By: smassey

Answer 4

One liner to deduplicate the list of dictionaries distinct_cur on the primary_key of doc

[i for n, i in enumerate(distinct_cur) if i.get('doc') not in [y.get('doc') for y in distinct_cur[n + 1:]]]

Answered By: Alec

Remove duplicates key from list of dictionaries python

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