BeautifulSoup: How do I extract all the <li>s from a list of <ul>s that contains some nested <ul>s?

Question

I’m a newbie programmer trying to jump in to Python by building a script that scrapes http://en.wikipedia.org/wiki/2000s_in_film and extracts a list of "Movie Title (Year)".
My HTML source looks like:

<h3>Header3 (Start here)</h3>
<ul>
    <li>List items</li>
    <li>Etc...</li>
</ul>
<h3>Header 3</h3>
<ul>
    <li>List items</li>
    <ul>
        <li>Nested list items</li>
        <li>Nested list items</li></ul>
    <li>List items</li>
</ul>
<h2>Header 2 (end here)</h2>

I’d like all the li tags following the first h3 tag and stopping at the next h2 tag, including all nested li tags.

firstH3 = soup.find('h3')

…correctly finds the place I’d like to start.

firstH3 = soup.find('h3') # Start here
uls = []
for nextSibling in firstH3.findNextSiblings():
    if nextSibling.name == 'h2':
        break
    if nextSibling.name == 'ul':
        uls.append(nextSibling)

…gives me a list uls, each with li contents that I need.

Excerpt of the uls list:

<ul>
...
    <li><i><a href="/wiki/Agent_Cody_Banks" title="Agent Cody Banks">Agent Cody Banks</a></i> (2003)</li>
    <li><i><a href="/wiki/Agent_Cody_Banks_2:_Destination_London" title="Agent Cody Banks 2: Destination London">Agent Cody Banks 2: Destination London</a></i> (2004)</li>
    <li>Air Bud series:
        <ul>
            <li><i><a href="/wiki/Air_Bud:_World_Pup" title="Air Bud: World Pup">Air Bud: World Pup</a></i> (2000)</li>
            <li><i><a href="/wiki/Air_Bud:_Seventh_Inning_Fetch" title="Air Bud: Seventh Inning Fetch">Air Bud: Seventh Inning Fetch</a></i> (2002)</li>
            <li><i><a href="/wiki/Air_Bud:_Spikes_Back" title="Air Bud: Spikes Back">Air Bud: Spikes Back</a></i> (2003)</li>
            <li><i><a href="/wiki/Air_Buddies" title="Air Buddies">Air Buddies</a></i> (2006)</li>
        </ul>
    </li>
    <li><i><a href="/wiki/Akeelah_and_the_Bee" title="Akeelah and the Bee">Akeelah and the Bee</a></i> (2006)</li>
...
</ul>

But I’m unsure of where to go from here.

Update:

Final Code:

lis = []
    for ul in uls:
        for li in ul.findAll('li'):
            if li.find('ul'):
                break
            lis.append(li)

    for li in lis:
        print li.text.encode("utf-8")

The if…break throws out the LI’s that contain UL’s since the nested LI’s are now duplicated.

Print output is now:

102 Dalmatians(2000)

10th & Wolf(2006)

11:14(2006)

12:08 East of Bucharest(2006)

13 Going on 30(2004)

1408(2007)

…

Asked By: danneu

||

Source

Answer 1

.findAll() works for nested li elements:

for ul in uls:
    for li in ul.findAll('li'):
        print(li)

Output:

<li>List items</li>
<li>Etc...</li>
<li>List items</li>
<li>Nested list items</li>
<li>Nested list items</li>
<li>List items</li>

Answered By: jfs

Answer 2

A list comprehension could work, too.

lis = [li for ul in uls for li in ul.findAll('li')]

Answered By: zachwill

Answer 3

import requests
from bs4 import BeautifulSoup
r = requests.get("https://www.w3schools.com/tags/tryit.asp?filename=tryhtml_list_test")
soup =   BeautifulSoup(r.content,"lxml")
w3schollsList = soup.find_all('body')
for w3scholl in w3schollsList:
    ulList = w3scholl.find_all('li')
    for li in ulList:
        print(li)

Note: here is to get the "li" inside the div we made

Answered By: ihsan güç

BeautifulSoup: How do I extract all the <li>s from a list of <ul>s that contains some nested <ul>s?

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