Django 1.11 TypeError context must be a dict rather than Context
Question:
Just received the Sentry error TypeError context must be a dict rather than Context. on one of my forms. I know it has something to do with Django 1.11, but I am not sure what to change to fix it.
Offending line
message = get_template('email_forms/direct_donation_form_email.html').render(Context(ctx))
Entire View
def donation_application(request):
if request.method == 'POST':
form = DirectDonationForm(data=request.POST)
if form.is_valid():
stripe.api_key = settings.STRIPE_SECRET_KEY
name = request.POST.get('name', '')
address = request.POST.get('address', '')
city = request.POST.get('city', '')
state = request.POST.get('state', '')
zip = request.POST.get('zip', '')
phone_number = request.POST.get('phone_number', '')
support = request.POST.get('support', '')
agree = request.POST.get('agree', '')
email_address = request.POST.get('email_address', '')
number = request.POST.get('number', '')
cvc = request.POST.get('cvc', '')
exp = request.POST.get('exp', '')
# token = form.cleaned_data['stripe_token'],
# exp_m = int(request.POST.get('exp_month', ''))
# exp_y = int(request.POST.get('exp_year', ''))
exp_month = exp[0:2]
exp_year = exp[5:9]
subject = 'New Donation'
from_email = settings.DEFAULT_FROM_EMAIL
recipient_list = ['deniselarkins@/////\\.com',
'charles@/////\\.net',
'marcmunic@/////\\.com',
]
token = stripe.Token.create(
card={
'number': number,
'exp_month': exp_month,
'exp_year': exp_year,
'cvc': cvc
},
)
customer = stripe.Customer.create(
email=email_address,
source=token,
)
total_support = decimal.Decimal(support) / 100
total_charge = decimal.Decimal(int(support)) / 100
# Charge the user's card:
charge = stripe.Charge.create(
amount=total_charge,
currency='usd',
description='Donation',
customer=customer.id
)
ctx = {
'name': name,
'address': address,
'city': city,
'state': state,
'zip': zip,
'phone_number': phone_number,
'email_address': email_address,
'agree': agree,
'charge': charge,
'customer': customer,
'total_support': total_support,
'total_charge': total_charge
}
message = get_template('email_forms/direct_donation_form_email.html').render(Context(ctx))
msg = EmailMessage(subject, message, from_email=from_email, to=recipient_list)
msg.content_subtype = 'html'
msg.send(fail_silently=True)
return redirect(
'/contribute/donation-support-thank-you/?name=' + name +
'&address=' + address +
'&state=' + state +
'&city=' + city +
'&zip=' + zip +
'&phone_number=' + phone_number +
'&email_address=' + email_address +
'&total_support=' + str(total_support) +
'&total_charge=' + str(total_charge)
)
context = {
'title': 'Donation Pledge',
}
return render(request, 'contribute/_donation-application.html', context)
Answers:
In Django 1.8+, the template’s render method takes a dictionary for the context parameter. Support for passing a Context instance is deprecated, and gives an error in Django 1.10+.
In your case, just use a regular dict instead of a Context instance:
message = get_template('email_forms/direct_donation_form_email.html').render(ctx)
You may prefer to use the render_to_string shortcut:
from django.template.loader import render_to_string
message = render_to_string('email_forms/direct_donation_form_email.html', ctx)
If you were using RequestContext instead of Context, then you would pass the request to these methods as well so that the context processors run.
message = get_template('email_forms/direct_donation_form_email.html').render(ctx, request=request)
message = render_to_string('email_forms/direct_donation_form_email.html', ctx, request=request)
Migrated from Django 1.8 to Django 1.11.6
Wherever i had a RequestContext class, there is a method flatten() wich return the result as a dict.
So if the class is RequestContext….
return t.render(context)
becomes
return t.render(context.flatten())
And in a case wich the context is is wrapped by Context(), just remove it. Because Context() is deprecated.
return t.render(Context(ctx))
becomes
return t.render(ctx)
For django 1.11 and after, context must be dict.
You can use:
context_dict = get_context_dict(context)
return t.render(context_dict)
or
context_dict = context.flatten()
return t.render(context_dict)
I got here because I had the same issue. I’m learning Django with Django Unleashed by Andrew Pinkham. It’s a book from 2015.
I found in the official documentation, that a dictionary must be passed to the context parameter and not a Context instance (from django.template.Context).
@Alasdair suggested to use render_to_string, but, at least in Django 3.2 the
render method use render_to_string method intrinsically.
def render(request, template_name, context=None, content_type=None, status=None, using=None):
"""
Return a HttpResponse whose content is filled with the result of calling
django.template.loader.render_to_string() with the passed arguments.
"""
content = loader.render_to_string(template_name, context, request, using=using)
return HttpResponse(content, content_type, status)
so, using just the render method could be better. I provide this answer because was the one that I was looking for and it may help some one reaching this Stack Overflow question.
Just received the Sentry error TypeError context must be a dict rather than Context. on one of my forms. I know it has something to do with Django 1.11, but I am not sure what to change to fix it.
Offending line
message = get_template('email_forms/direct_donation_form_email.html').render(Context(ctx))
Entire View
def donation_application(request):
if request.method == 'POST':
form = DirectDonationForm(data=request.POST)
if form.is_valid():
stripe.api_key = settings.STRIPE_SECRET_KEY
name = request.POST.get('name', '')
address = request.POST.get('address', '')
city = request.POST.get('city', '')
state = request.POST.get('state', '')
zip = request.POST.get('zip', '')
phone_number = request.POST.get('phone_number', '')
support = request.POST.get('support', '')
agree = request.POST.get('agree', '')
email_address = request.POST.get('email_address', '')
number = request.POST.get('number', '')
cvc = request.POST.get('cvc', '')
exp = request.POST.get('exp', '')
# token = form.cleaned_data['stripe_token'],
# exp_m = int(request.POST.get('exp_month', ''))
# exp_y = int(request.POST.get('exp_year', ''))
exp_month = exp[0:2]
exp_year = exp[5:9]
subject = 'New Donation'
from_email = settings.DEFAULT_FROM_EMAIL
recipient_list = ['deniselarkins@/////\\.com',
'charles@/////\\.net',
'marcmunic@/////\\.com',
]
token = stripe.Token.create(
card={
'number': number,
'exp_month': exp_month,
'exp_year': exp_year,
'cvc': cvc
},
)
customer = stripe.Customer.create(
email=email_address,
source=token,
)
total_support = decimal.Decimal(support) / 100
total_charge = decimal.Decimal(int(support)) / 100
# Charge the user's card:
charge = stripe.Charge.create(
amount=total_charge,
currency='usd',
description='Donation',
customer=customer.id
)
ctx = {
'name': name,
'address': address,
'city': city,
'state': state,
'zip': zip,
'phone_number': phone_number,
'email_address': email_address,
'agree': agree,
'charge': charge,
'customer': customer,
'total_support': total_support,
'total_charge': total_charge
}
message = get_template('email_forms/direct_donation_form_email.html').render(Context(ctx))
msg = EmailMessage(subject, message, from_email=from_email, to=recipient_list)
msg.content_subtype = 'html'
msg.send(fail_silently=True)
return redirect(
'/contribute/donation-support-thank-you/?name=' + name +
'&address=' + address +
'&state=' + state +
'&city=' + city +
'&zip=' + zip +
'&phone_number=' + phone_number +
'&email_address=' + email_address +
'&total_support=' + str(total_support) +
'&total_charge=' + str(total_charge)
)
context = {
'title': 'Donation Pledge',
}
return render(request, 'contribute/_donation-application.html', context)
In Django 1.8+, the template’s render method takes a dictionary for the context parameter. Support for passing a Context instance is deprecated, and gives an error in Django 1.10+.
In your case, just use a regular dict instead of a Context instance:
message = get_template('email_forms/direct_donation_form_email.html').render(ctx)
You may prefer to use the render_to_string shortcut:
from django.template.loader import render_to_string
message = render_to_string('email_forms/direct_donation_form_email.html', ctx)
If you were using RequestContext instead of Context, then you would pass the request to these methods as well so that the context processors run.
message = get_template('email_forms/direct_donation_form_email.html').render(ctx, request=request)
message = render_to_string('email_forms/direct_donation_form_email.html', ctx, request=request)
Migrated from Django 1.8 to Django 1.11.6
Wherever i had a RequestContext class, there is a method flatten() wich return the result as a dict.
So if the class is RequestContext….
return t.render(context)
becomes
return t.render(context.flatten())
And in a case wich the context is is wrapped by Context(), just remove it. Because Context() is deprecated.
return t.render(Context(ctx))
becomes
return t.render(ctx)
For django 1.11 and after, context must be dict.
You can use:
context_dict = get_context_dict(context)
return t.render(context_dict)
or
context_dict = context.flatten()
return t.render(context_dict)
I got here because I had the same issue. I’m learning Django with Django Unleashed by Andrew Pinkham. It’s a book from 2015.
I found in the official documentation, that a dictionary must be passed to the context parameter and not a Context instance (from django.template.Context).
@Alasdair suggested to use render_to_string, but, at least in Django 3.2 the
render method use render_to_string method intrinsically.
def render(request, template_name, context=None, content_type=None, status=None, using=None):
"""
Return a HttpResponse whose content is filled with the result of calling
django.template.loader.render_to_string() with the passed arguments.
"""
content = loader.render_to_string(template_name, context, request, using=using)
return HttpResponse(content, content_type, status)
so, using just the render method could be better. I provide this answer because was the one that I was looking for and it may help some one reaching this Stack Overflow question.