python function call with variable

Question

def test():
    print 'test'

def test2():
    print 'test2'

test = {'test':'blabla','test2':'blabla2'}
for key, val in test.items():
    key() # Here i want to call the function with the key name, how can i do so?

Asked By: pkdkk

||

Source

Answer 1

You could use the actual function objects themselves as keys, rather than the names of the functions. Functions are first class objects in Python, so it’s cleaner and more elegant to use them directly rather than their names.

test = {test:'blabla', test2:'blabla2'}

for key, val in test.items():
    key()

Answered By: John Kugelman

Answer 2

John has a good solution. Here’s another way, using eval():

def test():
        print 'test'

def test2():
        print 'test2'

mydict = {'test':'blabla','test2':'blabla2'}
for key, val in mydict.items():
        eval(key+'()')

Note that I changed the name of the dictionary to prevent a clash with the name of the test() function.

Answered By: chrisaycock

Answer 3

def test():
    print 'test'

def test2():
    print 'test2'

assign_list=[test,test2]

for i in assign_list:
    i()

Answered By: Surya

Answer 4

def test():
    print 'test'

def test2():
    print 'test2'

func_dict = {
    "test":test,
    "test2":test2
}


test = {'test':'blabla','test2':'blabla2'}
for key, val in test.items():
    func_dict[key]()

Answered By: Tangy_leprechaun

python function call with variable

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