How to create python bytes object from long hex string?

Question:

I have a long sequence of hex digits in a string, such as

000000000000484240FA063DE5D0B744ADBED63A81FAEA390000C8428640A43D5005BD44

only much longer, several kilobytes. Is there a builtin way to convert this to a bytes object in python 2.6/3?

Asked By: recursive

||

Answers:

Try the binascii module

from binascii import unhexlify
b = unhexlify(myhexstr)
Answered By: Crescent Fresh

You can do this with the hex codec. ie:

>>> s='000000000000484240FA063DE5D0B744ADBED63A81FAEA390000C8428640A43D5005BD44'
>>> s.decode('hex')
'x00x00x00x00x00x00HB@xfax06=xe5xd0xb7Dxadxbexd6:x81xfaxea9x00x00xc8Bx86@xa4=Px05xbdD'
Answered By: Brian
result = bytes.fromhex(some_hex_string)
Answered By: vili

Works in Python 2.7 and higher including python3:

result = bytearray.fromhex('deadbeef')

Note: There seems to be a bug with the bytearray.fromhex() function in Python 2.6. The python.org documentation states that the function accepts a string as an argument, but when applied, the following error is thrown:

>>> bytearray.fromhex('B9 01EF')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: fromhex() argument 1 must be unicode, not str`
Answered By: Jim Garrison
import binascii

binascii.a2b_hex(hex_string)

Thats the way I did it.

Answered By: JustPlayin
Categories: questions Tags: , ,
Answers are sorted by their score. The answer accepted by the question owner as the best is marked with
at the top-right corner.