Get Filename Without Extension in Python
Question:
If I have a filename like one of these:
1.1.1.1.1.jpg
1.1.jpg
1.jpg
How could I get only the filename, without the extension? Would a regex be appropriate?
Answers:
In most cases, you shouldn’t use a regex for that.
os.path.splitext(filename)[0]
This will also handle a filename like .bashrc correctly by keeping the whole name.
>>> import os
>>> os.path.splitext("1.1.1.1.1.jpg")
('1.1.1.1.1', '.jpg')
No need for regex. os.path.splitext is your friend:
os.path.splitext('1.1.1.jpg')
>>> ('1.1.1', '.jpg')
If I had to do this with a regex, I’d do it like this:
s = re.sub(r'.jpg$', '', s)
You can use stem method to get file name.
Here is an example:
from pathlib import Path
p = Path(r"\some_directorysubdirectorymy_file.txt")
print(p.stem)
# my_file
One can also use the string slicing.
>>> "1.1.1.1.1.jpg"[:-len(".jpg")]
'1.1.1.1.1'
If I have a filename like one of these:
1.1.1.1.1.jpg
1.1.jpg
1.jpg
How could I get only the filename, without the extension? Would a regex be appropriate?
In most cases, you shouldn’t use a regex for that.
os.path.splitext(filename)[0]
This will also handle a filename like .bashrc correctly by keeping the whole name.
>>> import os
>>> os.path.splitext("1.1.1.1.1.jpg")
('1.1.1.1.1', '.jpg')
No need for regex. os.path.splitext is your friend:
os.path.splitext('1.1.1.jpg')
>>> ('1.1.1', '.jpg')
If I had to do this with a regex, I’d do it like this:
s = re.sub(r'.jpg$', '', s)
You can use stem method to get file name.
Here is an example:
from pathlib import Path
p = Path(r"\some_directorysubdirectorymy_file.txt")
print(p.stem)
# my_file
One can also use the string slicing.
>>> "1.1.1.1.1.jpg"[:-len(".jpg")]
'1.1.1.1.1'