This is my code
def fahrenheit(T): return ((float(9)/5)*T + 32) temp = [0, 22.5, 40,100] F_temps = map(fahrenheit, temp)
This is mapobject so I tried something like this
for i in F_temps: print(F_temps) <map object at 0x7f9aa050ff28> <map object at 0x7f9aa050ff28> <map object at 0x7f9aa050ff28> <map object at 0x7f9aa050ff28>
I am not sure but I think that my solution was possible with Python 2.7,how to change this with 3.5?
You have to turn the map into a list or tuple first. To do that,
This is because maps are lazily evaluated, meaning the values are only computed on-demand. Let’s see an example
def evaluate(x): print(x) mymap = map(evaluate, [1,2,3]) # nothing gets printed yet print(mymap) # <map object at 0x106ea0f10> # calling next evaluates the next value in the map next(mymap) # prints 1 next(mymap) # prints 2 next(mymap) # prints 3 next(mymap) # raises the StopIteration error
When you use map in a for loop, the loop automatically calls
next for you, and treats the StopIteration error as the end of the loop. Calling
list(mymap) forces all the map values to be evaluated.
result = list(mymap) # prints 1, 2, 3
However, since our
evaluate function has no return value,
result is simply
[None, None, None]