chr() equivalent returning a bytes object, in py3k

Question:

Python 2.x has chr(), which converts a number in the range 0-255 to a byte string with one character with that numeric value, and unichr(), which converts a number in the range 0-0x10FFFF to a Unicode string with one character with that Unicode codepoint. Python 3.x replaces unichr() with chr(), in keeping with its “Unicode strings are default” policy, but I can’t find anything that does exactly what the old chr() did. The 2to3 utility (from 2.6) leaves chr calls alone, which is not right in general 🙁

(This is for parsing and serializing a file format which is explicitly defined in terms of 8-bit bytes.)

Asked By: zwol

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Answers:

Try the following:

b = bytes([x])

For example:

>>> bytes([255])
b'xff'
Answered By: Mark Byers

Consider using bytearray((255,)) which works the same in Python2 and Python3. In both Python generations the resulting bytearray-object can be converted to a bytes(obj) which is an alias for a str() in Python2 and real bytes() in Python3.

# Python2
>>> x = bytearray((32,33))
>>> x
bytearray(b' !')
>>> bytes(x)
' !'

# Python3
>>> x = bytearray((32,33))
>>> x
bytearray(b' !')
>>> bytes(x)
b' !'
Answered By: Guido U. Draheim
>>> import struct
>>> struct.pack('B', 10)
b'n'
>>> import functools
>>> bchr = functools.partial(struct.pack, 'B')
>>> bchr(10)
b'n'
Answered By: SangYoung Lee

In case you want to write Python 2/3 compatible code, use six.int2byte

Answered By: youfu

Yet another alternative (Python 3.5+):

>>> b'%c' % 65
b'A'
Answered By: Ecir Hana

simple replacement based on small range memoization (should work on 2 and 3), good performance on CPython and pypy

binchr = tuple([bytes(bytearray((b,))) for b in range(256)]).__getitem__

binchr(1) -> b'x01'
Answered By: Glushiator
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