Python can't open file "No such file or directory"

Question

def main():
    fh = open('lines.txt')
    for line in fh.readlines():
        print(line)

if __name__ == "__main__": main()

Directory files

I am on for-working.py file, and am trying to access the lines.txt file within the same working directory. But I get error

No such file or directory: ‘lines.txt’

Does python need to have an absolute path when opening files?

why doesn’t this relative path work here?

Running python 3.6

EDIT ^1 I’m running visualstudio code with the python package extension by Don Jayamanne, and “Code Runner” package to compile/execute python code

EDIT ^2 Full error:

Traceback (most recent call last):
  File "c:wwwEx_Files_Python_3_EssT(1)Ex_Files_Python_3_EssTExercise Files7 Loopsfor-working.py", line 11, in <module>
    if __name__ == "__main__": main()
  File "c:wwwEx_Files_Python_3_EssT(1)Ex_Files_Python_3_EssTExercise Files7 Loopsfor-working.py", line 7, in main
    fh = open('lines.txt', 'r')
FileNotFoundError: [Errno 2] No such file or directory: 'lines.txt'

EDIT ^3 checking sys.path

import sys
print(sys.path)

produces this information:

['c:\www\Ex_Files_Python_3_EssT(1)\Ex_Files_Python_3_EssT\Exercise Files\07 Loops', 
'C:\Users\Kagerjay\AppData\Local\Programs\Python\Python36\python36.zip', 'C:\Users\Kagerjay\AppData\Local\Programs\Python\Python36\DLLs', 'C:\Users\Kagerjay\AppData\Local\Programs\Python\Python36\lib', 'C:\Users\Kagerjay\AppData\Local\Programs\Python\Python36', 'C:\Users\Kagerjay\AppData\Local\Programs\Python\Python36\lib\site-packages']

EDIT ^4 checking os.getcwd()

Running

import os
print(os.getcwd())

Produces

c:wwwEx_Files_Python_3_EssT(1)Ex_Files_Python_3_EssTExercise Files

Well its definitely not in the right subdirectory (needs to cd 07 loops folder, that narrows the issue down

EDIT ^5 what is in lines.txt file

My lines.txt file i am opening looks like this. No extra whitespace or anything at start

01 This is a line of text
02 This is a line of text
03 This is a line of text
04 This is a line of text
05 This is a line of text

IN SUMMARY

Visual studio code’s Code runner extension needs to be tweaked slightly to open files within a subdirectory so any of the below answers would provide a more robust solution to be independent of any extension / dependencies with the IDE

import os
print(os.getcwd())

Is most useful for diagnosing problem to the current directory python interpreter sees

Asked By: Vincent Tang

||

Source

Answer 1

This should do the trick.

def main():
    fh = open('lines.txt')
    for line in fh.readlines():
        print(line)

if __name__ == "__main__":
    import os

    curr_dir = os.path.dirname(os.path.realpath(__file__))  # get's the path of the script
    os.chdir(curr_dir)  # changes the current path to the path of the script
    main()

Answered By: Ma0

Answer 2

Get the directory of the file, and join it with the file you want to open:

def main():
    dir_path = os.path.dirname(os.path.realpath(__file__))
    lines = os.path.join(dir_path, "lines.txt")
    fh = open(lines)
    for line in fh.readlines():
        print(line)

if __name__ == "__main__": main()

Answered By: thaavik

Answer 3

okay summary of working solutions to my problem from others not mentioned in post

Direct absolute path manually

def main():
    fh = open('lines.txt')
    for line in fh.readlines():
        print(line)

if __name__ == "__main__":
    import os

    curr_dir = 'c:\www\Ex_Files_Python_3_EssT(1)\Ex_Files_Python_3_EssT\Exercise Files\07 Loops'
    os.chdir(curr_dir)
    main()

I commented out unnecessary parts ... and open(lines at beginning

Below solution is very good for lazy implementation tests (e.g. copy-paste template), since all the absolute path correction code is up top seperated from everything else (my preferred solution)

import os
dir_path = os.path.dirname(os.path.realpath(__file__))
lines = os.path.join(dir_path, "lines.txt")
# open(lines)
# ...

def main():
    fh = open(lines)
    for line in fh.readlines():
        print(line)

if __name__ == "__main__": main()

Most robust solution would be this one below, since its self-contained only in the function definition when main() gets called. Original answer didn’t include the import os so I included it here

def main():
    import os
    dir_path = os.path.dirname(os.path.realpath(__file__))
    lines = os.path.join(dir_path, "lines.txt")
    fh = open(lines)
    for line in fh.readlines():
        print(line)

if __name__ == "__main__": main()

Answered By: Vincent Tang

Answer 4

I faced the same trouble today. The solution was outside the code, in the environment.

Shows the picture of VSCode settings editor

Command prompt in VSCode opens with the directory where VSCode executable is placed. When you execute the code, Python is searching for the file in the location where the VSCode executable is located.

This setting can be changed to the directory that you are working in(shown in figure). So when you are running the code in yourprog.py file, the interpretor is started in your working directory.

Then the VScode runner will do the way you are thinking.

Answered By: M M Kamalraj

Python can't open file "No such file or directory"

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