Error in nonlocal keyword in python

Question

I am trying to use nonlocal keyword in python in the following code. inner() is enclosed in outer() and I want to create a counter variable that will remember how many times inner() is called from outer(). ctr is defined in outer() and as nonlocal in inner().

But I am getting error as no binding for nonlocal 'ctr' found.

def inner1():
    nonlocal ctr
    ctr=ctr+1
    print(' ctr= {0}'.format(ctr))


def outer1():
    ctr=0
    for i in range(5):
        inner1()

outer1()

Asked By: bner341

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Source

Answer 1

inner() is enclosed in outer()

No, inner is not enclosed in outer (not defined within the scope of outer), you’re only calling inner from outer; there isn’t any closure here.

Answered By: Moses Koledoye

Error in nonlocal keyword in python

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