How to get the current log level in python logging module

Question:

I’m trying to create a basic logger that will be colored without external packages,

# these have to be the first functions so I can use it in the logger settings
def create_log_name(log_path="{}/log", filename="zeus-log-{}.log"):
    if not os.path.exists(log_path.format(os.getcwd())):
        os.mkdir(log_path.format(os.getcwd()))
    find_file_amount = len(os.listdir(log_path.format(os.getcwd())))
    full_log_path = "{}/{}".format(log_path.format(os.getcwd()), filename.format(find_file_amount + 1))
    return full_log_path


def set_color_value(levelname):
    log_set = {
        "INFO": "33[92m{}33[0m",
        "WARNING": "33[93m{}33[0m",
        "DEBUG": "33[94m{}33[0m",
        "ERROR": "33[91m{}33[0m",
        "CRITICAL": "33[91m{}33[0m"
    }
    return log_set[levelname].format(levelname)

logger = logging.getLogger("zeus-log")
logger.setLevel(logging.DEBUG)
file_handler = logging.FileHandler(
    filename=create_log_name(), mode="a+"
)
file_handler.setLevel(logging.DEBUG)
console_handler = logging.StreamHandler()
console_handler.setLevel(logging.DEBUG)
file_format = logging.Formatter(
    '%(asctime)s;%(name)s;%(levelname)s;%(message)s'
)
console_format = logging.Formatter(
    "[%(asctime)s {}] %(message)s".format(set_color_value()), "%H:%M:%S"
)
file_handler.setFormatter(file_format)
console_handler.setFormatter(console_format)
logger.addHandler(console_handler)
logger.addHandler(file_handler)

So as of right now, all I need to do is get the current log level that will be set in the logging.Formatter and send it to my little function:

console_format = logging.Formatter(
    "[%(asctime)s {}] %(message)s".format(set_color_value()), "%H:%M:%S"
)

Is it possible to get the current log level from the logging package?


For example, lets say I pass logger.INFO("test") I need a way to get that INFO part in as a string, from there, set_color_value("INFO") should return:

enter image description here

Asked By: wahwahwah

||

Answers:

Yes, you can check the logger level by

level = logger.level
Answered By: Milán Vásárhelyi

I decided to do this a different way and add color through the string itself with a level number:

def set_color(org_string, level=None):
    color_levels = {
        10: "33[36m{}33[0m",       # DEBUG
        20: "33[32m{}33[0m",       # INFO
        30: "33[33m{}33[0m",       # WARNING
        40: "33[31m{}33[0m",       # ERROR
        50: "33[7;31;31m{}33[0m"   # FATAL/CRITICAL/EXCEPTION
    }
    if level is None:
        return color_levels[20].format(org_string)
    else:
        return color_levels[int(level)].format(org_string)

So for example:

logger.info(set_color("test"))
logger.debug(set_color("test", level=10))
logger.warning(set_color("test", level=30))
logger.error(set_color("test", level=40))
logger.fatal(set_color("test", level=50))

Will output:

enter image description here

Answered By: wahwahwah

If you’re using the root logger, for example because you called logging.basicConfig() then you can use

import logging
logging.root.level

For example

if logging.DEBUG >= logging.root.level:
    # Do something
Answered By: bcattle

In your logger instance you can check it like this, as @Milán Vásárhelyi said:

myLogger.level

That will return the level as int. if you prefer to show the name, as string, you can do:

logging.getLevelName(myLogger.level)

As explained in this walk through the source code logger.level is often wrong.

You want logger.getEffectiveLevel()

To quote the source:

Here’s the takeaway: don’t rely on .level. If you haven’t explicitly set a level on your logger object, and you’re depending on .level for some reason, then your logging setup will likely behave differently than you expected it to.

Answered By: Dan MacNeil
Categories: questions Tags: , ,
Answers are sorted by their score. The answer accepted by the question owner as the best is marked with
at the top-right corner.