Print a sorted list

Question

Why executing the following:

print([7,1,0].sort())

produces:

None

while executing the following:

a = [7,1,0]
a.sort()
print(a)

produces:

[0, 1, 7]

?

Asked By: pebox11

||

Source

Answer 1

Because .sort() operates on the list and returns None, while print(sorted(a)) prints what you want but does not alter the list

Answered By: GPhilo

Answer 2

sort() sorts the list but returns None. You probably want sorted.

print(sorted([7,1,0]))

Answered By: 0x5453

Answer 3

The .sort() method sorts the list in place and returns None. The list becomes sorted, which is why printing the list displays the expected value. However, print(x.sort()) prints the result of sort(), and sort() returns None.

Answered By: Bryan Oakley

Answer 4

Because in the first example print([7,1,0].sort()) you are printing value returned by sort() and sort() does not return anything.
While later you are performing sort() on the list a and then printing the lista.

Sort() changes order of elements in the list a and does not return anything.

Use sorted() to get sorted list as returned value.

Answered By: Talita

Print a sorted list

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