Python: check for data type in list

Question

Is there a way to check if an instance of a specific data type is present in a list / dictionary, without explicitly checking every element / key?

I suspect the answer is no. If it does exist, though, I imagine it would be similar to the way you can use the in operator to search for specific elements / keys, like this:

3 in [1, 2, 3] # => True

except you’d be checking for an instance of a data type rather than a some specific value, like this:

int in [1,"a", 3.4] # => True

Any ideas?

Asked By: inconveniently_nonexempt_bee

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Source

Answer 1

Well in is actually syntactic sugar for __contains__, which does iterate over the contents of the list.

If you would like to use in to check for types instead; you could implement your own data structure (subclassing list) and override __contains__ to check for types:

class MyList(list):
    def __contains__(self, typ):
        for val in self:
            if isinstance(val, typ):
                return True
        return False

x = MyList([1, 2, 'a', 3])

print float in x # False
print str in x   # True

You could also take advantage of the any function:

def __contains__(self, typ):
    return any(isinstance(val, typ) for val in self)

print int in MyList([1, "a", 3.4]) # True
print int in MyList(["a", 3.4])    # False

As for whether this is doable without checking every element – no, it’s not. In the worst case scenario, you do end up checking every element.

Answered By: Bahrom

Answer 2

I think you can use isinstance(element, type).

I made a function:

def checkType(a_list):
    for element in a_list:
        if isinstance(element, int):
            print("It's an Integer")
        if isinstance(element, str):
            print("It's an string")
        if isinstance(element, float):
            print("It's an floating number")

numbers = [1, 2, 3]
checkType(numbers)

This outputs:

It's an Integer
It's an Integer
It's an Integer

Answered By: OuuGiii

Answer 3

you can do like this will be your input list and you can check on iterating on it and I got pass two times

a = [2, 4, 5, 6, '8', 9, 8]
for i in a:
    if i in [2, 8] and type(i) == int:
        print('pass')

Answered By: Tanveer Ahmad

Python: check for data type in list

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