Loop over 2 lists, repeating the shortest until end of longest

Question

I am sure there is an easy and obvious way to do this, but I have been googling and reading the docs and I just cannot find anything.

This is what I want to achieve:

la = ['a1', 'a2', 'a3', 'a4']
lb = ['b1', 'b2']
result = ['a1_b1', 'a2_b2', 'a3_b1', 'a4_b2']

I have a list of dates and some of them have something marked on them. I then have a much larger list of dates and I want to put the smallest list inside the bigger list as many times as possible. It will probably require some sort of loop as I need access to the dates in the larger list for the end result.

For some reason, I just cannot see a good way to do this.

Asked By: Mathias Nielsen

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Source

Answer 1

Try

result = ["_".join((i, j)) for i, j in itertools.izip(la, itertools.cycle(lb))]

Answered By: Sven Marnach

Answer 2

Assuming la is longer than lb:

>>> import itertools
>>> [x+'_'+y for x,y in zip(la, itertools.cycle(lb))]
['a1_b1', 'a2_b2', 'a3_b1', 'a4_b2']

itertools.cycle(lb) returns a cyclic iterator for the elements in lb.
zip(...) returns a list of tuples in which each element corresponds to an element in la coupled with the matching element in the iterator.

Answered By: snakile

Answer 3

import itertools
la = ['a1', 'a2', 'a3', 'a4']
lb = ['b1', 'b2']
for i, j in zip(la, itertools.cycle(lb)):
    print('_'.join((i,j)))

Answered By: wwii

Answer 4

Using only zip, just repeat the shorter list.

[x+'_'+y for x,y in zip(la, lb*2)]

Answered By: BSalita

Loop over 2 lists, repeating the shortest until end of longest

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