Python 2.7 getting user input and manipulating as string without quotations

The function input will also evaluate the data it just read as python code, which is not really what you want.

The generic approach would be to treat the user input (from sys.stdin) like any other file. Try

import sys
sys.stdin.readline()

If you want to keep it short, you can use raw_input which is the same as input but omits the evaluation.

testVar = raw_input("Ask user for something.")

The issue seems to be resolved in Python version 3.4.2.

testVar = input("Ask user for something.")

Will work fine.

If you want to use input instead of raw_input in python 2.x,then this trick will come handy

    if hasattr(__builtins__, 'raw_input'):
      input=raw_input

After which,

testVar = input("Ask user for something.")

will work just fine.

My Working code with fixes:

import random
import math
print "Welcome to Sam's Math Test"
num1= random.randint(1, 10)
num2= random.randint(1, 10)
num3= random.randint(1, 10)
list=[num1, num2, num3]
maxNum= max(list)
minNum= min(list)
sqrtOne= math.sqrt(num1)

correct= False
while(correct == False):
    guess1= input("Which number is the highest? "+ str(list) + ": ")
    if maxNum == guess1:
        print("Correct!")
        correct = True
    else:
        print("Incorrect, try again")

correct= False
while(correct == False):
guess2= input("Which number is the lowest? " + str(list) +": ")
if minNum == guess2:
     print("Correct!")
     correct = True
else:
    print("Incorrect, try again")

correct= False
while(correct == False):
    guess3= raw_input("Is the square root of " + str(num1) + " greater than or equal to 2? (y/n): ")
    if sqrtOne >= 2.0 and str(guess3) == "y":
        print("Correct!")
        correct = True
    elif sqrtOne < 2.0 and str(guess3) == "n":
        print("Correct!")
        correct = True
    else:
        print("Incorrect, try again")

print("Thanks for playing!")

This is my work around to fail safe in case if i will need to move to python 3 in future.

def _input(msg):
  return raw_input(msg)

We can use the raw_input() function in Python 2 and the input() function in Python 3.
By default the input function takes an input in string format. For other data type you have to cast the user input.

In Python 2 we use the raw_input() function. It waits for the user to type some input and press return and we need to store the value in a variable by casting as our desire data type. Be careful when using type casting

x = raw_input("Enter a number: ") #String input

x = int(raw_input("Enter a number: ")) #integer input

x = float(raw_input("Enter a float number: ")) #float input

x = eval(raw_input("Enter a float number: ")) #eval input

In Python 3 we use the input() function which returns a user input value.

x = input("Enter a number: ") #String input

If you enter a string, int, float, eval it will take as string input

x = int(input("Enter a number: ")) #integer input

If you enter a string for int cast ValueError: invalid literal for int() with base 10:

x = float(input("Enter a float number: ")) #float input

If you enter a string for float cast ValueError: could not convert string to float

x = eval(input("Enter a float number: ")) #eval input

If you enter a string for eval cast NameError: name ' ' is not defined
Those error also applicable for Python 2.