Square Every Digit of a Number in Python?

Question

Square Every Digit of a Number in Python?
if we run 9119 through the function, 811181 will come out, because 92 is 81 and 12 is 1.
write a code but this not working.

def sq(num):
words = num.split()  # split the text
for word in words:  # for each word in the line:
    print(word**2) # print the word

num = 9119
sq(num)

Asked By: Abhiseck

||

Source

Answer 1

We can use list to split every character of a string, also we can use "end" in "print" to indicate the deliminter in the print out.

def sq(num):
    words = list(str(num)) # split the text
    for word in words:  # for each word in the line:
        print(int(word)**2, end="") # print the word

num = 9119
sq(num)

Alternatively

return ''.join(str(int(i)**2) for i in str(num))

Answered By: Siong Thye Goh

Answer 2

def sq(num):
    z = ''.join(str(int(i)**2) for i in str(num))
    return int(z)

Answered By: dsugasa

Answer 3

We can also support input of negative numbers and zeros. Uses arithmetic operators (% and //) for fun.

def sq(num):
    num = abs(num)                             #Handle negative numbers
    output = str((num % 10)**2)                #Process rightmost digit 

    while(num > 0):        
        num //= 10                             #Remove rightmost digit       
        output = str((num % 10)**2) + output   #Add squared digit to output
    print(output)

Answered By: Jonathan Grandi

Answer 4

def square_digits(num):
    num = str(num)
    result = ''
    for i in num:
        result += str(int(i)**2)
    return int(result)
var = square_digits(123)
print(var)

Answered By: KrisChi

Answer 5

number=str(input("Enter the number :"))

def pc(number):

      digits = list(number)

      for j in digits:

      print(int(j)**2,end="")
 
pc(number)

Answered By: Athithya

Answer 6

You can try this variant:

def square_digits(num):
    return int(''.join(str(int(i)**2) for i in str(num)))

Answered By: Oleksandr

Square Every Digit of a Number in Python?

Question:

Answers: