How to send a message with discord.py without a command

Question:

import discord
import asyncio

client = discord.Client()
@client.event
async def on_ready():
    print("I'm ready.")

async def send(message):
    await client.send_message(client.get_channel("123456789"), message)

client.run("token")

loop = asyncio.get_event_loop()
loop.run_until_complete(send("hello"))

Hi, i want to make a GUI. When someone put in his name and press "OK" my discord bot should send a message. Basically i thought i call the async by it’s name, didn’t work. Then i made a event loop. worked with a print(), but the bot doesn’t send a message, so i thought it is not ready, when i put wait_until_ready() there it executed nothing, so i thought i have to put the client.run("token") before the event loop, didn’t work either.

can you guys help me? 🙂

Asked By: mauexe

||

Answers:

The reason your code is not working is because client.run is blocking, meaning that nothing after it will execute. This means your loop will never be reached.

To get around this, use client.loop.create_task.

The github of discord.py has an example of a background task, found here. You should be able to use this as reference. Currently the task posts a message to the given channel every minute, but you can easily modify it to wait for a specific action.

New discord.py versions

import discord
import asyncio

client = discord.Client()

async def my_background_task():
    await client.wait_until_ready()
    counter = 0
    channel = client.get_channel(id=123456789) # replace with channel_id
    while not client.is_closed():
        counter += 1
        await channel.send(counter)
        await asyncio.sleep(60) # task runs every 60 seconds

@client.event
async def on_ready():
    print('Logged in as')
    print(client.user.name)
    print(client.user.id)
    print('------')

client.loop.create_task(my_background_task())
client.run('token')

Older discord.py versions

import discord
import asyncio

client = discord.Client()

async def my_background_task():
    await client.wait_until_ready()
    counter = 0
    channel = discord.Object(id='channel_id_here')
    while not client.is_closed:
        counter += 1
        await client.send_message(channel, counter)
        await asyncio.sleep(60) # task runs every 60 seconds

@client.event
async def on_ready():
    print('Logged in as')
    print(client.user.name)
    print(client.user.id)
    print('------')

client.loop.create_task(my_background_task())
client.run('token')
Answered By: Benjin

For responsive behaviour, you have two options: you can write a on_message event handler, or use the discord.ext.commands module. I recommend using commands, as it’s more powerful and doesn’t keep everything in a single coroutine.

from discord.ext.commands import Bot

bot = Bot(command_prefix='!')

@bot.event
async def on_ready():
    print("I'm ready.")
    global target_channel
    target_channel = bot.get_channel("412678093006831617")

@bot.command()
async def send(*, message):                         
    global target_channel
    await bot.send_message(channel, message)

This would be called with !send Some message. The *, message syntax just tells the bot not to try and parse the message contents further.

Answered By: Patrick Haugh
import discord
from discord.ext import commands
client = commands.Bot(command_prefix='>')

@client.event
async def on_ready():
    print(f"Log : {client.user}")
    ch = await client.fetch_channel("enter id text channel")
    await ch.send(content="your content")


client.run("token")
Answered By: tre flse

I know this question is old but found a better hack to perform this action.
in your bot.py have a global variable for your messages and channel Id if needed

channelId = os.getenv('channelId')
token = os.getenv('discordBotToken')
intents = discord.Intents.default()

# inililzing discord client with default intents
client = discord.Client(intents=intents)

# Global message variable to be set externally and bot to be triggered
message = ""

# event triggered when the bot is ready
@client.event
async def on_ready():
    channel = client.get_channel(int(channelId)) # find the channel with the channel ID
    await channel.send(message) # send the message from the global variable
    await client.close() # close the client to stop the client blocking code

# method to be executed from an external file
def BotRun():
    client.run(token)

Then in your main.py import this file and

import bot as discordBot

discordBot.message = "hello!"
discordBot.BotRun()

This way u can call this bot without having it running in the background.

The only downside of this as u can expect is that we are closing the client and logging in every time we send a message.

Answered By: Prajwal Raju P
Categories: questions Tags: , , ,
Answers are sorted by their score. The answer accepted by the question owner as the best is marked with
at the top-right corner.