Python programming, getting the same value over and over instead of it increasing

Question

So I am working on assignment for college and am still very new to coding so here is the question. At one college, the tuition for a full-time student is $8,000 per semester. It has been announced that the tuition will increase by 3 percent each year for the next five years. Write a program with a loop that `displays the projected semester tuition amount for the next five years.

tuition_increase = 0.03
tuition = 8000
tuition_total = 0
years = 5

print('tuition_totaltyears')
print('--------------------')
for years in range (1, years + 1)
    tuition_total = (tuition * tuition_increase) + tuition
    print(tuition_total, '/t', years)

I keep getting the same value over and over instead of it increasing by the tuition increase for each year

Asked By: Matthew Lapriore

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Source

Answer 1

you don’t sum tuition_total value to tuition_total value calculated from the previous step try it on following way.

tuition_total = ((tuition * tuition_increase) + tuition) + tuition_total

or

tuition_total += (tuition * tuition_increase) + tuition

Answered By: coder

Answer 2

Here’s corrected one. First line after for is the correct formula for calculating compound interest. Note, that I start indexing years for it from zero.

print() changed to use .format() in order to get tabulated output.

tuition_increase = 0.03
tuition = 8000
tuition_total = 0
years = 5

print('tuition_totaltyears')
print('--------------------')
for years in range (0, years ):
    tuition_total = tuition * (1+tuition_increase)** years
    print('{0:<15} {1}'.format(int(tuition_total), years+1))

will print

tuition_total   years
--------------------
8000            1
8240            2
8487            3
8741            4
9004            5

Answered By: Mika72

Answer 3

You don’t need tuition_total just assign back to tuition, e.g.:

In []:
tuition_increase = 0.03
tuition = 8000
years = 5

print('tuitiontyears')
print('--------------------')
print(tuition, 't', 0)

for years in range (1, years + 1):
    tuition *= (1+tuition_increase)
    print(tuition, 't', years)

Out[]:
tuition years
--------------------
8000     0
8240.0   1
8487.2   2
8741.816     3
9004.07048   4
9274.1925944     5

As you can see you will need to fix your formatting.

You can also use itertools.accumulate() to do these things:

In []:
tuition_increase = 0.03
tuition = 8000
years = 5
print('{:10}{}'.format('tuition', 'years'))
print('-'*20)
for year, tuition in enumerate(it.accumulate(it.repeat(tuition, years+1), lambda x, y: x*(1+tuition_increase))):
    print('{:<10.2f}{}'.format(tuition, year))

Out[]:
tuition   years     
--------------------
8000.00   0         
8240.00   1         
8487.20   2         
8741.82   3         
9004.07   4         
9274.19   5

Answered By: AChampion

Answer 4

Small change need to be done.

tuition_increase = 0.03
tuition = 8000
tuition_total = 0
years = 5

print('tuition_totaltyears')
print('--------------------')
for years in range (1, years + 1):
    tuition = (tuition * tuition_increase) + tuition
    print(tuition, '/t', years)

Answered By: Ankur Alankar Biswal

Answer 5

Here is the suggested solution from Tony Gaddis’ book, Starting out with Python (Pearson Revel):

    tuition = 8000
    for i in range(1, 6):
        tuition *= 1.03
        if i == 1:
            print("In 1 year, the tuition will be $" + str(tuition) + ".")
        else:
            print("In "+str(i)+" years, the tuition will be $" + str(tuition) + ".")

Answered By: 1stYearPython.py

Answer 6

Here’s how I did it and got it right.

tuition = 8240.00
tuition1 = 8000
rate = 0.03

for year1 in range(1, 2):
    tuition1 = tuition1 * (1 + rate)
    print(f"In {year1} year, the tuition will be ${tuition1:.2f}.")
    for year in range (2, 6):
        tuition *= (1 + rate)
        print(f"In {year} years, the tuition will be ${tuition:.2f}.")

Answered By: Andres Pineda

Python programming, getting the same value over and over instead of it increasing

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