Split string into two parts only
Question:
I have a string
s = 'abcd qwrre qwedsasd zxcwsacds'
I want to split any string in only two parts at the first occurrence of a whitespace. i.e. a='abcd' and b='qwrre qwedsasd zxcwsacds'
If I use a, b=split(' ') it gives me an error because there are too many values to unpack.
Answers:
1.You can split the string like this.
a = temp.substring(0, s.indexOf(' '));
b = temp.substring(s.indexOf(' ') + 1);
2.or you can do:
a = s[0: s.find(' ')]
b = s[s.find(' ') + 1: ]
3.
a,b = s.split(' ', 1)
print(a)
print(b)
From the Python docs
str.split(sep=None, maxsplit=-1)
Return a list of the words in the string, using sep as the delimiter
string. If maxsplit is given, at most maxsplit splits are done (thus,
the list will have at most maxsplit+1 elements). If maxsplit is not
specified or -1, then there is no limit on the number of splits (all
possible splits are made).
'1 2 3'.split(maxsplit=1)
# ['1', '2 3']
#!python2
s='abcd qwrre qwedsasd zxcwsacds'
s1 = s[0: s.find(' ')]
s2 = s[s.find(' ') + 1: ]
print s1
print s2
'''
abcd
qwrre qwedsasd zxcwsacds
'''
You could use a,b = split(' ', 1).
The second argument 1 is the maximum number of splits that would be done.
s = 'abcd efgh hijk'
a,b = s.split(' ', 1)
print(a) #abcd
print(b) #efgh hijk
For more information on the string split function, see str.split in the manual.
You can use a standard string method partition which searches for a given separator and returns a 3-tuple consisting of string part before it, the separator itself, and the part after it.
>>> s = 'abcd qwrre qwedsasd zxcwsacds'
>>> s.partition(' ')
('abcd', ' ', 'qwrre qwedsasd zxcwsacds')
You can solve this problem by using python “star expression”.
s='abcd qwrre qwedsasd zxcwsacds'
a = s.split()
first, *second = a
second = " ".join(second)
“first” takes the first element of the list and ” *second” takes the remaining elements.
>>> first
'abcd'
>>> second
'qwrre', 'qwedsasd', 'zxcwsacds'
Try this:
s = 'abcd qwrre qwedsasd zxcwsacds'
s1 = s.split()[0]
s2 = ' '.join(s.split()[1:])
print(s1)
print(s2)
Output:
abcd
qwrre qwedsasd zxcwsacds
Or:
new_s = ''.join([' s ' if i.isspace() else i for i in s])
a,b = new_s.replace(' s','',1).split(' s ')
print(a)
print(b)
Output:
abcd
qwrre qwedsasd zxcwsacds
Or even better split also for tabs and newlines:
a,b = s.split(None,1)
print(a)
print(b)
Output:
abcd
qwrre qwedsasd zxcwsacds
You’re missing one more parameter in your split, the number of occurrences, try this;
s='abcd qwrre qwedsasd zxcwsacds'
>>> a, b = s.split(' ', 1)
>>> print(a, b)
So, there’s a second parameter you can pass as many have pointed out:
>>> a, b = "foo bar".split(' ', 1)
but nobody’s pointing this out:
>>> a, b = "foobar".split(' ', 1)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: need more than 1 value to unpack
You don’t want to be using this because it’s unsafe unless you’re guaranteed to have a string that has only the one space in it. It’s better to split it and then check for how many splits you’ve got and then unpack them:
>>> parts = "foo bar".split(' ', 1)
>>> if len(parts) == 2:
>>> a, b = parts
I have a string
s = 'abcd qwrre qwedsasd zxcwsacds'
I want to split any string in only two parts at the first occurrence of a whitespace. i.e. a='abcd' and b='qwrre qwedsasd zxcwsacds'
If I use a, b=split(' ') it gives me an error because there are too many values to unpack.
1.You can split the string like this.
a = temp.substring(0, s.indexOf(' '));
b = temp.substring(s.indexOf(' ') + 1);
2.or you can do:
a = s[0: s.find(' ')]
b = s[s.find(' ') + 1: ]
3.
a,b = s.split(' ', 1)
print(a)
print(b)
From the Python docs
str.split(sep=None, maxsplit=-1)
Return a list of the words in the string, using sep as the delimiter
string. If maxsplit is given, at most maxsplit splits are done (thus,
the list will have at most maxsplit+1 elements). If maxsplit is not
specified or -1, then there is no limit on the number of splits (all
possible splits are made).
'1 2 3'.split(maxsplit=1)
# ['1', '2 3']
#!python2
s='abcd qwrre qwedsasd zxcwsacds'
s1 = s[0: s.find(' ')]
s2 = s[s.find(' ') + 1: ]
print s1
print s2
'''
abcd
qwrre qwedsasd zxcwsacds
'''
You could use a,b = split(' ', 1).
The second argument 1 is the maximum number of splits that would be done.
s = 'abcd efgh hijk'
a,b = s.split(' ', 1)
print(a) #abcd
print(b) #efgh hijk
For more information on the string split function, see str.split in the manual.
You can use a standard string method partition which searches for a given separator and returns a 3-tuple consisting of string part before it, the separator itself, and the part after it.
>>> s = 'abcd qwrre qwedsasd zxcwsacds'
>>> s.partition(' ')
('abcd', ' ', 'qwrre qwedsasd zxcwsacds')
You can solve this problem by using python “star expression”.
s='abcd qwrre qwedsasd zxcwsacds'
a = s.split()
first, *second = a
second = " ".join(second)
“first” takes the first element of the list and ” *second” takes the remaining elements.
>>> first
'abcd'
>>> second
'qwrre', 'qwedsasd', 'zxcwsacds'
Try this:
s = 'abcd qwrre qwedsasd zxcwsacds'
s1 = s.split()[0]
s2 = ' '.join(s.split()[1:])
print(s1)
print(s2)
Output:
abcd
qwrre qwedsasd zxcwsacds
Or:
new_s = ''.join([' s ' if i.isspace() else i for i in s])
a,b = new_s.replace(' s','',1).split(' s ')
print(a)
print(b)
Output:
abcd
qwrre qwedsasd zxcwsacds
Or even better split also for tabs and newlines:
a,b = s.split(None,1)
print(a)
print(b)
Output:
abcd
qwrre qwedsasd zxcwsacds
You’re missing one more parameter in your split, the number of occurrences, try this;
s='abcd qwrre qwedsasd zxcwsacds'
>>> a, b = s.split(' ', 1)
>>> print(a, b)
So, there’s a second parameter you can pass as many have pointed out:
>>> a, b = "foo bar".split(' ', 1)
but nobody’s pointing this out:
>>> a, b = "foobar".split(' ', 1)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: need more than 1 value to unpack
You don’t want to be using this because it’s unsafe unless you’re guaranteed to have a string that has only the one space in it. It’s better to split it and then check for how many splits you’ve got and then unpack them:
>>> parts = "foo bar".split(' ', 1)
>>> if len(parts) == 2:
>>> a, b = parts