How to get the concrete class name as a string?

Question

I want to avoid calling a lot of isinstance() functions, so I’m looking for a way to get the concrete class name for an instance variable as a string.

Any ideas?

Asked By: user7305

||

Source

Answer 1

 instance.__class__.__name__

example:

>>> class A():
    pass
>>> a = A()
>>> a.__class__.__name__
'A'

Answered By: SilentGhost

Answer 2

<object>.__class__.__name__

Answered By: Morendil

Answer 3

you can also create a dict with the classes themselves as keys, not necessarily the classnames

typefunc={
    int:lambda x: x*2,
    str:lambda s:'(*(%s)*)'%s
}

def transform (param):
    print typefunc[type(param)](param)

transform (1)
>>> 2
transform ("hi")
>>> (*(hi)*)

here typefunc is a dict that maps a function for each type. transform gets that function and applies it to the parameter.

of course, it would be much better to use ‘real’ OOP

Answered By: Javier

How to get the concrete class name as a string?

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