Point in polygon using shapely?

Question

I am running the following script which I believe should be returning TRUE for the point being in the polygon but it is returning FALSE.

from shapely import geometry

polygon = [(-1571236.8349707182, 8989180.222117377), (1599362.9654156454, 8924317.946336618), (-1653179.0745812152, 8922145.163675062), (-1626237.6614402141, 8986445.107619021)]

Point_X = -1627875.474
Point_Y = 8955472.968

line = geometry.LineString(polygon)
point = geometry.Point(Point_X, Point_Y)

print(line.contains(point))

When I plot the polygon and point in Matlab I get the following shape

from matplotlib import pylab as plt
poly = [[-1571236.8349707182, 8989180.222117377],
    [1599362.9654156454, 8924317.946336618],
    [-1653179.0745812152, 8922145.163675062],
    [-1626237.6614402141, 8986445.107619021]]

x = [point[0] for point in poly]
y = [point[1] for point in poly]

p1 = [-1627875.474, 8955472.968]
p2 = [-1627875.474, 8955472.968]
plt.plot(x,y,p1[0],p1[1],'*r',p2[0],p2[1],'*b')
plt.show()

Any idea why the shapely script is returning FALSE?

Asked By: user2512696

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Source

Answer 1

What you are testing is whether your point is on the object LineString.

If you want to test that the point is in the polygon you must use the contains methods of class Polygon

from shapely import geometry

polygon = [(-1571236.8349707182, 8989180.222117377), (1599362.9654156454, 8924317.946336618), (-1653179.0745812152, 8922145.163675062), (-1626237.6614402141, 8986445.107619021)]

Point_X = -1627875.474
Point_Y = 8955472.968

line = geometry.LineString(polygon)
point = geometry.Point(Point_X, Point_Y)
polygon = geometry.Polygon(line)

print(polygon.contains(point))

ouput

True

see https://shapely.readthedocs.io/en/latest/manual.html

Answered By: PilouPili

Answer 2

This code uses geopandas to find point(s) within polygon(s).

import geopandas as gpd
points_gpd = gpd.GeoDataFrame(geometry=gpd.points_from_xy(x, y)) #point coordinates to geopandas dataframe
polygons_gpd = gpd.GeoDataFrame(geometry=polygons) #polygons is a list of shapely polygons
pt2poly = gpd.sjoin(points_gpd,polygons_gpd, predicate='within').index_right #for each point index in the points, it stores the polygon index containing that point

Answered By: foxtrotmikew

Point in polygon using shapely?

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