python "all" function making list empty

Question

I am new to python and was learning its builtins but function all()
is not behaving as expected i don’t know why.Here is my code

n=map(int,input().strip().split())
print(all([j>0 for j in n]))
print(list(n)) #this line returning empty list

Here are my inputs:

1 2 3 4 5 -9

And my output:

False

Does function all changes the original map object(values)? but something like this is not mentioned in given function definition on the docs link.

Thanks in advance

Asked By: Devesh

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Source

Answer 1

Map returns a generator object which you exhausted in your all function. Therefore when you call list on n, since n is empty/exhausted, it returns an empty list.

To fix just make n a list in the first place.

n=list(map(int,input().strip().split()))
print(all([j>0 for j in n]))
print(n)

Answered By: MooingRawr

python "all" function making list empty

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