How to convert dataframe to dictionary in pandas WITHOUT index

Question:

I have a dataframe df as follows:

| name  | coverage |
|-------|----------|
| Jason | 25.1     |

I want to convert it to a dictionary.
I used the following command in pandas :

dict=df.to_dict()

The output of dict gave me the following:

{'coverage': {0: 25.1}, 'name': {0: 'Jason'}} 

I do not want the 0 in my output. I believe this is captured because of the column index in my dataframe df.
What can I do to eliminate 0 in my output
( I do not want index to be captured.) expected output :

{'coverage': 25.1, 'name': 'Jason'} 
Asked By: Symphony

||

Answers:

dict1 = df.to_dict('records')

or

dict2 = df.to_dict('list')

list: keys are column names, values are lists of column data

records: each row becomes a dictionary where key is column name and value is the data in the cell

Answered By: asimo

When I see your dataset with 2 columns I see a series and not a dataframe.

Try this: d = df.set_index('name')['coverage'].to_dict() which will convert your dataframe to a series and output that.

However, if your intent is to have more columns and not a common key you could store them in an array instead using ‘records’. d = df.to_dict('r').
`

Runnable code:

import pandas as pd

df = pd.DataFrame({
    'name': ['Jason'],
    'coverage': [25.1]
})

print(df.to_dict())
print(df.set_index('name')['coverage'].to_dict())
print(df.to_dict('r'))

Returns:

{'name': {0: 'Jason'}, 'coverage': {0: 25.1}}
{'Jason': 25.1}
[{'name': 'Jason', 'coverage': 25.1}]

And one more thing, try to avoid to use variable name dict as it is reserved.

Answered By: Anton vBR

if its just 1 column, slice the 1 column (it gets converted to Series) wrapping in a dict function

dict( myDF.iloc[:, -1] )
# [: , -1] means: return all rows, return last column)

{Jason: 25.1}
Answered By: jon rios

you can do something like this:

data.to_dict('list')

#output:
#{'Feeling low in energy-slowed down': [2, 4, 2, 4]}
Answered By: Ch Usman