How do I check the users input in Python3?

Question

So my code says this:

a = input("Choose a letter")

if a == "A" or "B" or "D":
cr = "false" 

elif a == "C":
  cr = "true"

if cr == "false":
 print("Sorry you did not asnwer correctly")
 import sys
 sys.exit()

elif cr == "true":
 print("Well done!")

But for some reason, whatever I put, it says it is wrong. Any help? I am new to python and have come from Lua.

Asked By: Sriyesh Bogadapati

||

Source

Answer 1

if a == "A" or "B" or "D": this evaluates to TRUE always. Because "B" or "D" always evaluates to TRUE everytime. So this might boil down to if 0 or 1 or 1 no matter what.

To fix this you need compare after every conditional operator.
if a == "A" or a == "B" or a == "D":

Answered By: Vineeth Sai

Answer 2

if a == "A" or "B" or "D":
   cr = "false"

Is wrong. You want:

if a == "A" or a == "B" or a == "D":
   cr = "false"

One nice thing you could do is this:

if a in [ 'A', 'B', 'D' ]:
   cr = "false"

Or even better rewrite your script to this:

a = input("Choose a letter")

if a == 'C':
 print("Well done!")
else:
 print("Sorry you did not asnwer correctly")
 import sys
 sys.exit()

Answered By: Red Cricket

How do I check the users input in Python3?

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