Python Nested loops: printed seats

You aren’t making use of num_cols but instead hard-coding column C. You should make the upper bound of the column based on num_cols.

Change:

while c2 <= 'C':

to:

while c2 < chr(ord('A') + num_cols):

Using a for loop instead of a while loop here could help ease the solution and optimize ouputs

rows = 2
columns = 3
l = ['a','b','c']

for i in range(1, rows +1):
    for j in range(1, columns + 1):
        print('{}{} '.format(i, l[j-1]), end='')
# 1a 1b 1c 2a 2b 2c 

columns = 0
# No output

Why do I think first of

import itertools
print(' '.join(''.join(x) for x in itertools.product('12', 'ABC')))

?

s1 = 1
while s1 <= num_rows and num_cols != 0:
    s2 = 'A'
    while s2 <= 'C':
        print('%s%s' % (s1,s2), end = ' ')
        s2 = chr(ord(s2) + 1)
s1 += 1

print()

I don’t know if it’s the cleanest, but it makes the most sense to me:

num_rows = 2
num_cols = 3

letter1 = '1'
letter2 = 'A'

for row in range(num_rows): # sets maximum changes to letter1.
   letter2 = 'A' # makes sure letter2 starts over after the inner loop first finishes.
   for col in range(num_cols): # sets maximum changes to letter2.
      print(letter1 + letter2, end=' ') # Print before incrementing letter2.
      letter2 = chr(ord(letter2) + 1) # converts 'A' to its unicode value, increments it by one, then converts it back to a letter.
   letter1 = chr(ord(letter1) + 1) # only runs after the inner loop is done to increment letter1 for the next loop.

num_row = 2
num_col = 3


i = 1
if num_rows and num_cols > 0:
    while i <= num_rows:    
        seat = 'A'
        while seat <= 'C':
            print('%s%s' %(i,seat), end=" ")
            seat = chr(ord(seat)+1)
        i +=1
print()

"Output returns correctly when I test with 2 rows and 3 columns or with 5 rows and 3 columns. However, when I test with 0 columns, it returns "1A 1B 1C 2A 2B 2C 3A 3B 3C 4A 4B 4C 5A 5B 5C" when it should return nothing. I tried changing c2 = ‘A’ into c2 = num_cols, but didn’t change anything." Add an if statement to make sure there are existing chairs. If there isn’t a column or row than their isn’t a chair

for i in range(num_rows):
    letter = "A"
    num = i+1 #initially 0, so making it 0 + 1 .. and so on
    
    for j in range(num_cols):
        
        print('{}{}'.format(num,letter), end= ' ')
        letter =chr(ord(letter)+1)  #getting the unicode of the letter and incrementing it and changing back to ASCII character

num_rows = int(input())
num_cols = int(input())

row = 1    # establish start point to count rows
for i in range(num_rows):  # iterate num_rows 
    seat = 'A'  # establish start point to count cols
    for j in range(num_cols): # iterate num_cols
        print('{}{}'.format(row, seat), end=' ')  # format outputs with space 
        seat = chr(ord(seat) + 1)   # convert character to integer and increment 
    row = (row +1)   # increment
print()

num_rows = int(input())
num_cols = int(input())


i = 1
for row in range(num_rows):
    j = 'A'
    for col in range(num_cols):
    print(f'{i}{j}', end=' ') # Print before incrementing letter2.
    j = chr(ord(j) + 1)
i = i + 1 # only runs after the inner loop is done to increment letter1 for the next loop.
print()

This is what I got from taking a snippet from @vash_the_stampede and some code from @Martin Tovmassian over on a post about how to find letters in a range.

num_rows = int(input())
num_cols = int(input())

rows = num_rows
columns = num_cols
from string import ascii_letters

def range_alpha(start_letter, end_letter):
  return ascii_letters[
    ascii_letters.index(start_letter):ascii_letters.index(end_letter) + 1
  ]
l = (range_alpha('A', 'Z'))

for i in range(1, rows +1):
    for j in range(1, columns + 1):
        print('{}{} '.format(i, l[j-1]), end='')

columns = 0
print()

I hope this helps someone trying to figure it out. I know this could be cleaner but I’m still in the middle of learning the basics of programming in Python.

Can be done using for loops, this way in my opinion is easier

num_rows = int(input())
num_cols = int(input())

letter = "A B C D E F G H I J K L M N O P Q R S T U V W X Y Z"
l = letter.split(" ")

for i in range(num_rows):
    for j in range(num_cols):
        print(f'{i+1}{l[j]}', end = " ")

print()

num_rows = int(input())
num_cols = int(input())

rows = 1
while rows <= num_rows:
    seat_letter = 'A'
    for j in range(num_cols):
        print("{}{}".format(rows, seat_letter),end=' ')
        seat_letter = chr(ord(seat_letter) + 1)
    rows += 1
print()

num_rows = int(input())
num_cols = int(input())

row = 1 
cols = '?'
while row <= num_rows:  
    cols = 'A'
    while cols < chr(ord('A') + num_cols):  
        print(f'{row}{cols}', end = ' ')
        cols = chr(ord(cols) + 1)
    row = row + 1

This has worked for me.