*args returns a list containing only those arguments that are even

Question

I’m learning python and in an exercise I need to write a function that takes an arbitrary number of arguments and returns a list containing only those arguments that are even.

My code is wrong I know: (But what is wrong with this code ?)

def myfunc(*args):
    for n in args:
        if n%2 == 0:
            return list(args)
myfunc(1,2,3,4,5,6,7,8,9,10)

Asked By: Aarón Más

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Source

Answer 1

Do a list-comprehension which picks elements from args that matches our selection criteria:

def myfunc(*args):
    return [n for n in args if n%2 == 0]

print(myfunc(1,2,3,4,5,6,7,8,9,10))
# [2, 4, 6, 8, 10]

Answered By: Austin

Answer 2

This also could be helpful, however, the previous comment looks more advanced:

def myfunc(*args):
    lista = []
    for i in list(args):
        if not i % 2:
            lista.append(i)
    return lista

Answered By: mahyar khatiri

Answer 3

Pick evens

def myfunc(*args):
    abc = []
    for n in args:
        if n%2==0:
            abc.append(n) 
    return abc

Answered By: Sanket Patil

Answer 4

def myfunc(*args):
    x=[]
    for i in list(args):
        if i%2==0:
            x.append(i)
    return x

Answered By: naruto

Answer 5

def myfunc(*args):
    mylist = []
    for x in list(args):
        if x % 2 == 0:
            mylist.remove(x)
    return mylist

Answered By: Nahean Islam

Answer 6

def myfunc(*args):
    even=[]
    for n in args:
        if n %2==0:
            even.append(n)
        else:
            pass
        
    return even
myfunc(1,2,3,4,8,9)

Answered By: Mr.Monk

Answer 7

def myfunc(*args):
    #solution 1
    # Create an empty list
    mylist = []
    for number in args:
        if number %2 == 0:
            mylist.append(number)
        else:
            pass
    # return the list
    return mylist
    
    #solution 2
    # Uses a list comprehension that includes the logic to find all evens and the list comprehension returns a list of those values
    # return [n for n in args if n%2 == 0]

Answered By: Jay

Answer 8

You need to create an empty list to contain the even numbers. Also convert your arguments to a list. Then append the even numbers to the newly created list.

def myfunc(*args):
new_list = []
for num in list(args):
    if num % 2 == 0:
        new_list.append(num)
else:
    pass
return new_list

Answered By: Moses

Answer 9

def myfunc(*args):
    return [x for x in args if not x&1]

Answered By: pham tan

*args returns a list containing only those arguments that are even

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