Sending locally hosted photo on telegram bot

Question:

I’m using api.telegram.bot and requests to send messages and images.

requests.get(url + 'sendMessage', params=dict(chat_id=send_to_user_id,text="Messo"))

This is working fine. My telegram user is able to receive the message “Messo”.

Now, I’m trying to use sendPhoto to send an image that I have hosted on my local drive.

path = "kings/test_screenie1.png"
requests.get(url + 'sendPhoto', params=dict(chat_id=send_to_user_id, photo=open(path,'rb')))

I do not get any exceptions, however, my user is not receiving the image. The output I get in Jupyter notebook is: <Response [414]>

My .ipynb file, where this code is running, is located in: /Users/abc/Desktop/webproject/play0.ipynb

My image file is located in: /Users/abc/Desktop/webproject/kings/test_screenie1.png

I am running this on Mac OS.

Asked By: Gen Tan

||

Answers:

Please, try this one:

requests.post(url + 'sendPhoto', data={'chat_id': send_to_user_id}, files={'photo': open('/Users/abc/Desktop/webproject/kings/test_screenie1.png', 'rb')})

I have tested locally on my bot, this approach works for me.

Hope, works for you.

Answered By: Artem Rys
Sub telegram_pruebas_photo()

    Const URL = "https://api.telegram.org/bot"
    Const TOKEN = "5657164377:AAFyybu06zS5_o3ge__gT2XJCh3tqhHIbww"
    Const METHOD_NAME = "/sendPhoto?"
    Const CHAT_ID = "714106364"
    
    Const FOLDER = "C:UsersPertfectPictures"
    Const JPG_FILE = "monkey.png"
    
    Dim data As Object, key
    Set data = CreateObject("Scripting.Dictionary")
    data.Add "chat_id", CHAT_ID
    
    ' generate boundary
    Dim BOUNDARY, s As String, n As Integer
    For n = 1 To 16: s = s & Chr(65 + Int(Rnd * 25)): Next
    BOUNDARY = s & CDbl(Now)

    Dim part As String, ado As Object
    For Each key In data.keys
        part = part & "--" & BOUNDARY & vbCrLf
        part = part & "Content-Disposition: form-data; name=""" & key & """" & vbCrLf & vbCrLf
        part = part & data(key) & vbCrLf
    Next
    ' filename
    part = part & "--" & BOUNDARY & vbCrLf
    part = part & "Content-Disposition: form-data; name=""photo""; filename=""" & JPG_FILE & """" & vbCrLf & vbCrLf
    
    ' read jpg file as binary
    Dim jpg
    Set ado = CreateObject("ADODB.Stream")
    ado.Type = 1 'binary
    ado.Open
    ado.LoadFromFile FOLDER & JPG_FILE
    ado.Position = 0
    jpg = ado.read
    ado.Close

    ' combine part, jpg , end
    ado.Open
    ado.Position = 0
    ado.Type = 1 ' binary
    ado.Write ToBytes(part)
    ado.Write jpg
    ado.Write ToBytes(vbCrLf & "--" & BOUNDARY & "--")
    ado.Position = 0

    Dim req As Object, reqURL As String
    Set req = CreateObject("MSXML2.XMLHTTP")
    reqURL = URL & TOKEN & METHOD_NAME
    With req
        .Open "POST", reqURL, False
        .setRequestHeader "Content-Type", "multipart/form-data; boundary=" & BOUNDARY
        .send ado.read
        MsgBox .responseText
    End With

End Sub

Function ToBytes(str As String) As Variant

    Dim ado As Object
    Set ado = CreateObject("ADODB.Stream")
    ado.Open
    ado.Type = 2 ' text
    ado.Charset = "_autodetect"
    ado.WriteText str
    ado.Position = 0
    ado.Type = 1
    ToBytes = ado.read
    ado.Close

End Function
Answered By: user20040808