How to split list based on characters and then make sub-lists?
Question:
How do I split a list into sub-lists, and then further split that to make each character an independent value?
I need to do this all inside of Python, version 3.6.5. The list will be in integers.
I need to convert
[123, 456]
into
[[1,2,3], [4,5,6]]
EDIT:
And after I have done that, how do I print the first character of the first sublist?
Note: Splitting integer in Python? and Turn a single number into single digits Python don’t solve or answer my problem, as they do not explain how to make sub-lists out of them.
Answers:
For example, using list comprehension:-
my_list = ['123', '456']
[list(x) for x in my_list]
If my_list is a list of integers:-
my_list = [123, 456]
[[int(x) for x in str(n)] for n in my_list]
A simple list comprehension will do, the idea is iterate over the characters in the string representation of the numbers:
[[int(x) for x in str(s)] for s in l]
How do I split a list into sub-lists, and then further split that to make each character an independent value?
I need to do this all inside of Python, version 3.6.5. The list will be in integers.
I need to convert
[123, 456]
into
[[1,2,3], [4,5,6]]
EDIT:
And after I have done that, how do I print the first character of the first sublist?
Note: Splitting integer in Python? and Turn a single number into single digits Python don’t solve or answer my problem, as they do not explain how to make sub-lists out of them.
For example, using list comprehension:-
my_list = ['123', '456']
[list(x) for x in my_list]
If my_list is a list of integers:-
my_list = [123, 456]
[[int(x) for x in str(n)] for n in my_list]
A simple list comprehension will do, the idea is iterate over the characters in the string representation of the numbers:
[[int(x) for x in str(s)] for s in l]