How to create rank column in Python based on other columns

Question

I have a python dataframe that looks like the following:

This dataframe has been sorted in descending order by 'transaction_count'. I want to create another column in that dataframe called 'rank' that contains the count of occurrences of cust_ID. My desired output would look something like the following:

For cust_ID = 1234 with transaction_count = 4, the rank would be 1, for the next appearance of cust_ID = 1234, the rank would be 2 and so on.

I tried the following among other things:

df['rank'] = df["cust_ID"].value_counts()
df.head(10)

But the rank column gets created as all NaN values

Any suggestions on how to approach this would be greatly appreciated!

Asked By: user3116949

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Source

Answer 1

Use groupby + cumcount:

df['rank'] = df.groupby('cust_ID').cumcount() + 1
print(df['rank'])

Output

0    1
1    2
2    1
3    1
4    2
5    3
Name: rank, dtype: int64

Answered By: Dani Mesejo

Answer 2

you can do:

df['rank'] = df.groupby('cust_ID')['transaction_count'].rank(ascending=False)

Output:

    cust_ID     associate_ID    transaction_count   rank
0   1234           608          4                   1.0
1   1234           785          1                   2.0
2   4789           345          2                   1.0
3   3456           268          5                   1.0
4   3456           725          3                   2.0
5   3456           795          1                   3.0

Note that this gives not only the counts, but also the rank of the transaction, based on the transaction_count value.

Answered By: Quang Hoang

How to create rank column in Python based on other columns

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