call list of function using list comprehension

Question

can I call a list of functions and use list comprehension?

def func1():
    return 1

def func2():
    return 2

def func3():
    return 3

fl = [func1, func2, func3]

fl[0]()
fl[1]()
fl[2]()

I know I can do

for f in fl:
    f()

but can I do below ?

[f() for f in fl]

A additional question for those kind people, if my list of functions is in class, for example

class F:
    
    def __init__(self):
        self.a, self.b, self.c = 0, 0, 0
        
    def func1(self):
        self.a += 1

    def func2(self):
        self.b += 1

    def func3(self):
        self.c += 1

    fl = [func1, func2, func3]

fobj = F()

for f in fobj.fl:
    f()

does it work?

Asked By: Jerry Gao

||

Source

Answer 1

>>> [f() for f in fl]
[1, 2, 3]

Absolutely 🙂

Answered By: Mike Lewis

Answer 2

Yes, you can – the functions get called as intended.

Answered By: Alexander Gessler

Answer 3

Yes, you can. The resultant list will hold the return values of your functions.

Answered By: nmichaels

Answer 4

Of course you can as Fábio Diniz said 🙂

However for the class method when used as a callable, an object must be given as an argument:

fobj = F()

for f in fobj.fl:
    f(fobj)

The object must be given as an argument to the callable because when you look at the definition of the method def funcX(self): the method needs one argument self

Answered By: P2bM

call list of function using list comprehension

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